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lora16 [44]
2 years ago
12

Select the correct answer from each drop-down menu.

Mathematics
1 answer:
Marina86 [1]2 years ago
3 0

Based on the inscribed quadrilateral conjecture: trapezoid QPRS can be inscribed in a circle because its opposite angles are supplementary.

<h3>What is the Inscribed Quadrilateral Conjecture?</h3>

The inscribed quadrilateral conjecture states that the opposite angle of any inscribed quadrilateral are supplementary to each other. That is, they have a sum of 180 degrees.

From the diagram given, the opposite angles in the trapezoid, 115 + 65 = 180 degrees.

Therefore, we can conclude that: trapezoid QPRS can be inscribed in a circle because its opposite angles are supplementary.

Learn more about the inscribed quadrilateral conjecture on:

brainly.com/question/12238046

#SPJ1

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At a rate of 4.25% over 24 months. If he pays $51.00 in interest, what was the original amount of his loan?
Alexxandr [17]
I = PRT.....rearrange.....P = I / RT

P = 51 / (0.0425* 2).....I used 2 because 24 months = 2 yrs
P = 51 / 0.085
P = 600 <===

6 0
4 years ago
Gabriel is designing equally sized horse stalls that are each in the shape of a rectangular prism. Each stall must be 9 feet hig
Andrews [41]

Answer:

The equation is 9x(x+2)=1,080.

The solution of the equation is x=10.

Step-by-step explanation:

The volume of a rectangular prism is found using the formula V = l · w · h, where l is the length, w is the width, and h is the height.

Let x ft be the widht of the stall, then the length of the stall is x+2 ft. If each stall must be 9 ft high, then the volume of the stall is V=x\cdot (x+2)\cdot 9=9x(x+2)\ ft^3.

The volume of each stall is 1,080\ ft^3, then

9x(x+2)=1,080,\\ \\x(x+2)=120,\\ \\x^2+2x-120=0,\\ \\D=2^2-4\cdot (-120)=4+480=484=22^2,\\ \\x_{1,2}=\dfrac{-2\pm 22}{2}=-12,\ 10.

The width cannot be negative, thus, x=10.

5 0
3 years ago
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
Write the equation of a line where slope = 2 and (1,3) is on the line in slope intercept form
vazorg [7]
Y = 3x + 0 is what i got though check my math to be sure 
5 0
4 years ago
7.
jek_recluse [69]

Answer:

$1.129

Step-by-step explanation:

7 0
3 years ago
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