Answer:
Step-by-step explanation:
There is a point V with ration 6 to 2, therefore we must find the coordinates of point V and the distance from A to V
<u>According to the graph</u>

α≅27°
V=2*8.94/6 (ratio 6:2)
V=2.98mile

coordinates of V = (2,65;1.35)
Distance from A to V

finally
Mary's mistake is to take the 6 to 2 ratio as the distance traveled from the globe only in the x direction
60 x 40%
60 x .40 = 24
The drama club washed 24 cars on Sunday.
Hope this helps. :)
Answer: c = 9
Step-by-step explanation:
12-9=3+9=12
Answer:
1st problem: b) 
2nd problem: c) 
Step-by-step explanation:
1st problem:
The formula/equation you want to use is:

where
t=number of years
A=amount he will owe in t years
P=principal (initial amount)
r=rate
n=number of times the interest is compounded per year t.
We are given:
P=2500
r=12%=.12
n=12 (since there are 12 months in a year and the interest is being compounded per month)

Time to clean up the inside of the ( ).


----------------------------------------------------
2nd Problem:
Compounded continuously problems use base as e.

P is still the principal
r is still the rate
t is still the number of years
A is still the amount.
You are given:
P=2500
r=12%=.12
Let's plug that information in:
.
Answer:
Latest time he can leave to be home by a quarter before 5 is 4:13
Step-by-step explanation:
Given Max's trip home takes 32 minutes. we have to find the time at which he can leave to be home by a quarter before 5.
quarter before 5 means 4:45
Max's takes 32 min to come to home so he has to leave 32 minutes before the given time.
Hence, latest time he can leave to be home by a quarter before 5 is 4:45-32 = 4:13