Answer:
The range of possible temperatures is the interval [80.5°,95.5°]
Step-by-step explanation:
Let
x -----> possible temperatures for that day.
we know that
The absolute value inequality of the difference of the possible temperatures and the temperature at noon must be less than or equal to 7.5° F
so

Solve the absolute-value inequality
<em>First case (positive case)</em>

Adds 88 both sides


<em>Second case (negative case)</em>

Multiply by -1 both sides

Adds 88 both sides


therefore
The range of possible temperatures is the interval [80.5°,95.5°]