What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7 ?

Mathematics

2 answers:

Salsk061 [2.6K]3 years ago

6 0

Answer:

$\frac{2}{3}$ is the Slope of a line that is perpendicular to a given line equation -2y=3x+7

Step-by-step explanation:

We are given here with the equation of the line $-2y=3x+7$ or we can write this equation as $y=\frac{-3}{2}x+\frac{-7}{2}$

the general equation of the line $y=mx+b$ where m is the slope and b is the y-intercept.

Compare the given equation with general equation we get,

the value of slope(m) $=\frac{-3}{2}$

The slope of line perpendicular to a line is, $m_{perpendicular}=\frac{-1}{m}$

Since, the slope of the given line is, m= $\frac{-3}{2}$

then, $m_{perpendicular}=\frac{-1}{\frac{-3}{2} }$ $=\frac{2}{3}$

Therefore, the slope of a line that is perpendicular to a line whose equation is -2y=3x+7 is, $\frac{2}{3}$

jarptica [38.1K]3 years ago

4 0

The answer is $\frac{2}{3}$

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