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alexandr402 [8]
3 years ago
11

What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7 ?

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
6 0

Answer:

\frac{2}{3} is the Slope of a line that is perpendicular to a given line equation -2y=3x+7

Step-by-step explanation:

We are given here with the equation of the line -2y=3x+7 or we can write this equation as y=\frac{-3}{2}x+\frac{-7}{2}

the general equation of the line y=mx+b  where m is the slope and b is the y-intercept.

Compare the given equation with general equation we get,

the value of  slope(m) =\frac{-3}{2}

The slope of line perpendicular to a line is, m_{perpendicular}=\frac{-1}{m}

Since, the slope of the given line is, m=\frac{-3}{2}

then, m_{perpendicular}=\frac{-1}{\frac{-3}{2} }=\frac{2}{3}

Therefore, the slope of a line that is perpendicular to a line whose equation is -2y=3x+7 is, \frac{2}{3}

jarptica [38.1K]3 years ago
4 0
The answer is \frac{2}{3}
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