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Natali [406]
3 years ago
14

a woodworker wants to cut a board that is 6.432 feet long into 4 equal-length pieces. How long will each of the cut boards be?

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
3 0

Answer:

I think it's 1.608

Step-by-step explanation:

6.432 divided by 4.

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If the area of a baseball diamond (shape of a square) is 8100 ft squared, how would you find the distance from 1st base to 3rd b
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Answer:

  • Exact distance = 90\sqrt{2} feet
  • Approximate distance = 127.2792 feet.

===========================================================

Explanation:

The area of the square is 8100 square feet, abbreviated ft^2.

Apply the square root to find the distance from any base to its adjacent counterpart (eg: from 1st to 2nd base). So we get sqrt(8100) = 90 ft as that side distance. Notice that 90*90 = 8100.

If you were to draw a line from 1st base to 3rd base, then you would split the square into two congruent right triangles. Each right triangle is isosceles (the two legs being 90 ft each).

Use the pythagorean theorem to find the hypotenuse.

a^2 + b^2 = c^2\\\\c = \sqrt{a^2+b^2}\\\\c = \sqrt{90^2+90^2}\\\\c = \sqrt{2*90^2}\\\\c = \sqrt{2}*\sqrt{90^2}\\\\c = \sqrt{2}*90\\\\c = 90\sqrt{2} \ \text{ ... exact distance}\\\\c \approx 127.2792 \ \text{ ... approximate distance}\\\\

The distance from 1st to 3rd base is roughly 127.2792 feet.

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2 years ago
2 x 6/7 <br><br> SEND HELP!!!!!!!!!!!
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Answer: C. 2 6/7

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8 0
3 years ago
It’s a new semester! Students are grouped into three clubs, which each has 10, 4 and 5 students. In how many ways can teacher se
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Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.

So there are 3 clubs:

  • Club A, with 10 students.
  • Club B, with 4 students.
  • Club C, with 5 students.

The possible combinations of 2 students from different clubs are

  • Club A with club B
  • Club A with club C
  • Club B with club C.

The number of combinations for each of these is given by the product between the number of students in the club, so we get:

  • Club A with club B: 10*4 = 40
  • Club A with club C: 10*5 = 50
  • Club B with club C. 4*5 = 20

For a total of 40 + 50 + 20 = 110 different combinations.

This means that there are 110 different ways in which 2 students from different clubs can be selected.

If you want to learn more about combination and selections, you can read:

brainly.com/question/251701

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2 years ago
A line is a collection of __________.
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A line is a collection of points in a linear direction that goes on infinitely in opposite directions.
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3 years ago
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C is your correct answer. Good luck.
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