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Airida [17]
3 years ago
13

Max has a drawer full of green and red socks. He has three times times as many red socks subtracted from four times as many gree

n socks which he believes is 50 socks. Half the number of green socks plus one-third of the number of red socks is 36. How many of each colour does he have?
Mathematics
1 answer:
monitta3 years ago
7 0

Answer:

There are 42 red colour socks and 44 green color socks

Step-by-step explanation:

Let there are r red socks and g green socks.

ATQ,

He has three times times as many red socks subtracted from four times as many green socks which he believes is 50 socks.

4g-3r=50 ....(1)

Half the number of green socks plus one-third of the number of red socks is 36.

\dfrac{g}{2}+\dfrac{r}{3}=36\\\\3g+2r=216\ .....(2)

Multiply equation (1) by 2 and equation (2) by 3.

8g-6r = 100 ....(3)

9g +6r = 648 ....(4)

Add equation (3) and (4)

8g-6r + 9g +6r = 100+648

17g = 748

g = 44

Put the value of g in equation (1).

4(44)-3r=50

176-3r = 50

176-50 = 3r

r = 42

Hence, there are 42 red colour socks and 44 green color socks.

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Step-by-step explanation:

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4 years ago
I need to find the derivative. I’m not very good at this so I am answer asap would be sosososo helpful
Bingel [31]

Answer:

See below.

Step-by-step explanation:

First, notice that this is a composition of functions. For instance, let's let f(x)=\sqrt{x} and g(x)=7x^2+4x+1. Then, the given equation is essentially f(g(x))=\sqrt{7x^2+4x+1}. Thus, we can use the chain rule.

Recall the chain rule: \frac{d}{dx}[f(g(x))]=f'(g(x))\cdot g'(x). So, let's find the derivative of each function:

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