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3 years ago

Complete the function f(x)=2x-5

Mathematics

1 answer:

Grace [21]3 years ago

7 0

Replace X in the equation with the values in the table and calculate:

2X-5:

2(-4) -5 = -8 -5 = -13

2(-2)-5 = -4-5 = -9

2(1)-5 = 2-5 = -3

2(3)-5 = 6-5 = 1

2(5)-5 = 10-5 = 5

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Can someone help me my grade are bad

Likurg_2 [28]

Answer:

8.31

Step-by-step explanation:

Using the Pythagorean Theorem:

$a^2+b^2=c^2$

$10^2+b^2=13^2$

$100+b^2=169$

$b^2=69$

$b = \sqrt{69}$

$b = 8.306623863$

The side length for $x$ , rounded to the nearest hundredths, would be 8.31.

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3 years ago

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Simplify the product using FOIL (4x-3)(3x+5)

Sphinxa [80]

$(4x-3)(3x+5) \\ \\ 12x^2 + 20x - 9x - 15 \\ \\ 12x^2 + 11x - 15 \\ \\$

The final result is: 12x<span>² + 11x - 15</span>

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3 years ago

Multiply (3x+2) (4x+5)

maksim [4K]

Answer:

So all you need to do is Combine like terms which gives you a answer of

12x2 + 23x + 10 Hope this helps :)

Step-by-step explanation:

8 0

3 years ago

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Find the slope of the line y<br> = -1/8x + 7/6

Elenna [48]

Answer:

The slope is -1/8 and the y intercept is 7/6

Step-by-step explanation:

This equation is in slope intercept form

y = mx+b where m is the slope and b is the y intercept

y = -1/8 x + 7/6

The slope is -1/8 and the y intercept is 7/6

7 0

3 years ago

Calculate the length of AB using Sine rule

vovikov84 [41]

Answer:

Approximately $22.2\; \rm m$ .

Step-by-step explanation:

By sine rule, the length of each side of a triangle is proportional to the sine value of the angle opposite to that side. For example, in this triangle $\triangle ABC$ , angle $\angle A$ is opposite to side $BC$ , while $\angle C$ is opposite to side $AB$ . By sine rule, $\displaystyle \frac{BC}{\sin{\angle A}} = \frac{AB}{\sin \angle C}$ .

It is already given that $BC = 22.4\; \rm m$ and $\angle A = 58^\circ$ . The catch is that the value of $\angle C$ needs to be calculated from $\angle A$ and $\angle B$ .

The sum of the three internal angles of a triangle is $180^\circ$ . In $\triangle ABC$ , that means $\angle A + \angle B + \angle C = 180^\circ$ . Hence,

$\begin{aligned}\angle C &= 180^\circ - \angle A - \angle B \\ &= 180^\circ - 58^\circ - 65^\circ \\ &= 57^\circ\end{aligned}$ .

Apply the sine rule:

$\begin{aligned} & \frac{BC}{\sin{\angle A}} = \frac{AB}{\sin \angle C} \\ \implies & AB = \frac{BC}{\sin{\angle A}} \cdot \sin \angle C \end{aligned}$ .

$\begin{aligned}AB &= \frac{BC}{\sin{\angle A}} \cdot \sin \angle C \\ &= \frac{22.4\; \rm m}{\sin 58^\circ} \times \sin 57^\circ \\ &\approx 22.2\; \rm m\end{aligned}$ .

5 0

3 years ago