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3 years ago

What the value 0 in degrees

Mathematics

1 answer:

mart [117]3 years ago

8 0

Answer:

45 degrees

Step-by-step explanation:

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Jenna bought books for $3 each and a game for $5. She spent a total of $26. How many books did she buy?

OleMash [197]

Answer:

she bought 7 books and 1 game. 1.)each=multiplication. 2.)and= addition.

Step-by-step explanation:

3.)26-5(the game)=21 divide by 3=7 books

4.)p-5=x divided by 3

3 0

3 years ago

Please I need help it’s an emergency

Hunter-Best [27]

Answer:

A. $4\sqrt{6}$

Step-by-step explanation:

Applying the leg rule which is:

$\frac{Hypotenuse}{leg} = \frac{leg}{part}$

Hypotenuse = 4 + 8 = 12

Leg = x

Part = 8

Plug in the values

$\frac{12}{x} = \frac{x}{8}$

Cross multiply

$x*x = 8*12$

$x^2 = 96$

$\sqrt{x^2} = \sqrt{96}$

$x = \sqrt{16 * 6}$

$x = 4\sqrt{6}$

6 0

3 years ago

Exercise 5.2. Suppose that X has moment generating function

soldi70 [24.7K]

Answer:

a) Mean, E(X) = - 0.5

Variance = = 9.25

b) $M_{X}(t)=E(e^{tX})$

⇒ $=\sum e^{tx}p(x)$

⇒ $=\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}$

Step-by-step explanation:

Given:

moment generating function of X as:

MX(t) = $\frac{1}{2} + \frac{1}{3}e^{-4t} + \frac{1}{6} e^{5t}$

a) Now

Mean, E(X) = $M_{X}'(t=0)$

Thus,

$M_{X}'(t)=\frac{1}{3}(-4)e^{-4t}+\frac{1}{6}(5)e^{5t}$

$M_{X}'(t)=\frac{-4}{3}e^{-4t}+\frac{5}{6}e^{5t}$

also,

$E(X^{2})=M_{X}''(t=0)$

Thus,

$M_{X}''(t)=\frac{-4}{3}(-4)e^{-4t}+\frac{5}{6}(5)e^{5t}$

$M_{X}''(t)=\frac{16}{3}e^{-4t}+\frac{25}{6}e^{5t}$

Therefore,

Mean, E(X) = $M_{X}'(t=0)=\frac{-4}{3}e^{-4(0)}+\frac{5}{6}e^{5(0)}$

Mean, E(X) = - 0.5

and

$E(X^{2})=M_{X}''(t=0)=\frac{16}{3}e^{-4(0)}+\frac{25}{6}e^{5(0)}$

$E(X^{2})$ = 9.5

also,

Variance(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

b) Now,

Let f(x) be the PMF of X

Thus,

$M_{X}(t)=E(e^{tX})$

⇒ $=\sum e^{tx}p(x)$

⇒ $=\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}$

Therefore,

at x = 0, P(x) = $\frac{1}{2}$

at x= - 4 ,P(x) = $\frac{1}{3}$

at x = 5, P(x) = $\frac{1}{6}$

Thus,

E(X) = $\sum xP(x)=0(\frac{1}{2})+(-4)(\frac{1}{3})+5(\frac{1}{6})$

E(X) = - 0.5

also, $E(X^{2})=\sum x^{2}P(x)=0^{2}(\frac{1}{2})+(-4)^{2}(\frac{1}{3})+5^{2}(\frac{1}{6})$

$E(X^{2})$ = 9.5

Hence,

Var(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

4 0

4 years ago

Use the following bond listing for Pacific Bell to answer the following:

monitta

Answer:

D- 99 1/4 ; $992.50

Step-by-step explanation:

you use the list of bonds to eventually get D- 99 1/4

3 0

2 years ago

the cost of having one shirt laundered is 6 dollars. each additional shirt costs 4 dollars. write the explicit and recursive for

Katarina [22]

Answer:

<h3>explicit formula- a(n)=6+4(n-1)</h3><h3>recursive formula- a(n)=a(n)-1 +4; a(1)=6</h3>

Step-by-step explanation:

4 0

3 years ago