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3 years ago

lamar paid $93 for a bicycle that was on sale for 60% if its original price. What was the original price of the bicycle?

Mathematics

2 answers:

lesya692 [45]3 years ago

6 0

For this case we propose a rule of three, in order to know the original price of the bicycle:

$ 93 ----------------> 60%

x ---------------------> 100%

Where the variable "x" represents the original cost of the bicycle. So:

$x = \frac {100 * 93} {60}\\x = \frac {9300} {60}\\x = 155$

Thus, the original cost of the bike was $ 155

ANswer:

$155

Rzqust [24]3 years ago

5 0

Answer:

$155.00 was the original price

Step-by-step explanation:

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lianna [129]

585 hotdogs in 45 minutes.
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3 years ago

1) 6a + 5a = −11

dimaraw [331]

Answer:

6a + 5a = 11

6a + 5a=

11a

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2 years ago

The sales of a grocery store had an average of $8,000 per day. The store introduced several advertising campaigns in order to in

oksano4ka [1.4K]

Answer:

Null hypothesis: $\mu \leq 8000$

Alternative hypothesis: $\mu > 8000$

$z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2$

$p_v =P(Z>2)=0.0228$

Step-by-step explanation:

1) Data given and notation

$\bar X=8300$ represent the sample mean

$\sigma=1200$ represent the population standard deviation

$n=64$ sample size

$\mu_o =800$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 8000, the system of hypothesis are :

Null hypothesis: $\mu \leq 8000$

Alternative hypothesis: $\mu > 8000$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2$

4) P-value

Since is a one-side upper test the p value would given by:

$p_v =P(Z>2)=0.0228$

5) Conclusion

If we compare the p value and the significance level assumed, for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than $8000.