Answer:
The shaded area is 314.2 cm²
Step-by-step explanation:
Here we note that the shape consists of two small circles and one larger circle
The diameter of the larger semicircle is subtended by the two smaller semicircles, the small semicircle closer to the left of the internal circumference of the larger semicircle is shaded one while the one on the right is without color,
Therefore,
Diameter of larger semicircle = 2 × 10 = 20 cm
Based on the diagram, the shaded area is observed to be;
Shaded area = Area of semicircle formed by larger diameter or 20 cm + Area area formed by the small semicircle close to the right of the internal circumference of the larger semicircle - Area area formed by the other smaller semicircle
Since the diameter and therefore the areas of the two small semicircles are equal, we have;
Shaded area = Area formed by the complete larger semicircle = Area of semicircle formed by larger diameter or 20 cm
∴ Shaded area = π·D²/4 = π×20²/4 = 100×3.142 cm² = 314.2 cm².
400$
Explanation:
In 1992, the price is 28000$ and 9600$ in 1996 so in 4 years the value the car lost is 18400$
Dividing 18400 by 4 years we get 4600 depreciation value per year.
Between 1996 and 1998 there is 2 years
So in 1998 the value of the car will be:
9600 (value in 1996) - 2x4600 = 400$
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A is the right option! Because 0.40 should be in second equation with the x to represent the number of stamps multiply by 40 cents.
