I think it should equal 70 but not 100%

Recall that a circle of radius 2 centered at the origin has equation

where the positive root gives the top half of the circle in the x-y plane. The definite integral corresponds to the area of the right half of this top half. Since the area of a circle with radius

is

, it follows that the area of a quarter-circle would be

.
You have

, so the definite integral is equal to

.
Another way to verify this is to actually compute the integral. Let

, so that

. Now

Recall the half-angle identity for cosine:

This means the integral is equivalent to
Answer:
The Answer is B 8+ 6=14
Step-by-step explanation:
14-8=6
8+6=14
14-6=8
Slope intercept
y=mx+b
m=sllope
given
m=-5
find b
y=-5x+b
given
(2,5)
means x=2 and y=5 is true
5=-5(2)+b
5=-10+b
add 10
15=b
y=-5x+15
Answer:
Step-by-step explanation:
i. kilograms 958+72+80=1110 ii.grams we know that 1 kg is 1000g so 1110kg= 1110x1000=1110000g