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kompoz [17]
3 years ago
10

there are 4 oranges and 2 tangerines in a basket. Which fraction describes the part of the basket that is orange​

Mathematics
2 answers:
Pepsi [2]3 years ago
6 0

Answer:

4/6

Step-by-step explanation:

You know that there is a total of 6 fruits in the basket.(you can find the total by adding the number of each item together.)

Then you simply find the total amount of oranges(4).

"There are 4 oranges out of the 6 fruits in the basket"/

So, 4/6.

<em>Hope this helped! :)</em>

Romashka-Z-Leto [24]3 years ago
4 0

Answer:

4/6

Step-by-step explanation:

The total number of fruits the basket have is 4+2 =6.

so lets fix the denominator as 6 .

now the question is basically asking you to tell how many fruits are oranges out of those 6 .

if you look at it has alredy toled you have 6 oranges .

now the fraction we get is :

4/6

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125% of what number is 25
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We can create a equation to find out.

since we are finding a number where when multiplied by 1.25(this is the decimal form of the percentage) gives us 25, we know that the number we are finding is less than 25. here is the equation.

1.25(x)=25

divide both sides by 1.25 to get "x" alone.

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Answer 10 and 11 for 10! Points <br>          <br>        
Andrej [43]
Number 10 equals C. 31.5 ounces
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Find the slope of the line that passes through the points (2,5) and (-8,5).
balu736 [363]
Y₂-y₁
--------
x₂-x₁

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3 0
3 years ago
A line passes through the point (8,-9) and has a slope of -5/2. Write an equation in slope intercept form for this line.
noname [10]

Answer:

y = - \frac{5}{2} x + 11

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - \frac{5}{2} , then

y = - \frac{5}{2} x + c ← is the partial equation

To find c substitute (8, - 9) into the partial equation

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y = - \frac{5}{2} x + 11 ← equation of line

4 0
3 years ago
Find the magnitude of a vector with initial point A(3, 4, 10) and terminal point B(8, 4, –2).
Fantom [35]

Answer:

B

Step-by-step explanation:

Use the distance formula in 3 dimensions

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2+(z_{2}-z_{1})^2      }

with (x₁, y₁, z₁ ) = (3, 4, 10) and (x₂, y₂, z₂ ) = (8, 4, - 2)

d = \sqrt{(8-3)^2+(4-4)^2+(-2-10)^2}

   = \sqrt{5^2+0^2+(-12)^2}

    = \sqrt{25+144}

    = \sqrt{169}

     = 13 → B

4 0
3 years ago
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