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matrenka [14]
3 years ago
7

Match each verbal description to its equivalent function rule as applied to the given function below.

Mathematics
1 answer:
stepladder [879]3 years ago
5 0
The top-left graph goes with the bottom-right equation, y=90(1/4)^x

The bottom-left graph goes with the top-right equation, y = 120(3/4)^x

The top-right graph goes with the bottom-left equation, y = 120(1/4)^x

The bottom-right graph goes with the top-left equation, y = 90(3/4)^x

y=90(1/4)^x has a larger percent decrease than y = 90(3/4)^x
cause if you multiply a number by 1/4, that's smaller than multiplying number by 3/4. so y=90(1/4)^x decreases really fast

same with the y = 120(3/4)^x ones
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What is x? -3(2x-7)+5=2x-9
vitfil [10]

Answer:

x=4.375

Step-by-step explanation:

-3(2x-7)+5=2x-9

-6x+21+5=2x-9

-6x+26=2x-9

-6x-2x+26=2x-2x-9

-8x+26=-9

-8x+26-26=-9-26

-8x=-35

-8x/-8=-35/-8

x=4.375

4 0
3 years ago
Read 2 more answers
Please help me with this , it would mean alot​
algol [13]

Answer:

Step-by-step explanation:

21-26. a = v - u / t

=> a = 47 - 19 / 5

=> a = 28 / 5

=> a = 5.6 m/s²

27-32. avg. speed = distance / time

=> 40 m / 10 s

=> 4 m/s

33-38. velocity = distance / time

=> v = 150 / 40

=> v = 15 / 4

=> v = 3.75 m/s

4 0
2 years ago
Please help!!!!
Yakvenalex [24]

Answer:

  D.  X-7

Step-by-step explanation:

The table tells you that when x=7, g(x) = 0. In order for g(7) to be zero, at least one factor must be zero when x=7. The only factor on the list that is zero when x=7 is (x-7).

6 0
3 years ago
Which is a simplified form of the following expression? 6c^2+2.5d - d + 2c^2-3d
melisa1 [442]
By collecting like terms we have:

6 {c}^{2}  + 2 {c}^{2}  + 2.5d - d  - 3d \\  \\ 8 {c}^{2}  - 1.5d
3 0
2 years ago
Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent
goblinko [34]

Answer:

y(x)=x^2+5x

Step-by-step explanation:

Given: y'=\sqrt{4y+25}

Initial value: y(1)=6

Let y'=\dfrac{dy}{dx}

\dfrac{dy}{dx}=\sqrt{4y+25}

Variable separable

\dfrac{dy}{\sqrt{4y+25}}=dx

Integrate both sides

\int \dfrac{dy}{\sqrt{4y+25}}=\int dx

\sqrt{4y+25}=2x+C

Initial condition, y(1)=6

\sqrt{4\cdot 6+25}=2\cdot 1+C

C=5

Put C into equation

Solution:

\sqrt{4y+25}=2x+5

or

4y+25=(2x+5)^2

y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}

y(x)=x^2+5x

Hence, The solution is y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4} or y(x)=x^2+5x

4 0
3 years ago
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