Given that the chip has a dimension of 8 mm by 8 mm which can be written as 0.8 cm by 0.8 cm, is drawn to scale and the dimensions of the plot is 4 cm by 4 cm, the scale of the drawing will be:
0.8 cm is represented by 4 cm
thus;
4 cm rep 0.8 cm
1 cm rep 0.2 cm
The answer is:
1 cm rep 0.2 cm
Since sin(2x)=2sinxcosx, we can plug that in to get sin(4x)=2sin(2x)cos(2x)=2*2sinxcosxcos(2x)=4sinxcosxcos(2x). Since cos(2x) = cos^2x-sin^2x, we plug that in. In addition, cos4x=cos^2(2x)-sin^2(2x). Next, since cos^2x=(1+cos(2x))/2 and sin^2x= (1-cos(2x))/2, we plug those in to end up with 4sinxcosxcos(2x)-((1+cos(2x))/2-(1-cos(2x))/2)
=4sinxcosxcos(2x)-(2cos(2x)/2)=4sinxcosxcos(2x)-cos(2x)
=cos(2x)*(4sinxcosx-1). Since sinxcosx=sin(2x), we plug that back in to end up with cos(2x)*(4sin(2x)-1)
Answer:
x=12
Step-by-step explanation:
ab=dc so 15=x+3 you subtract 3 from both sides... x=12
Answer:
D . 9 .1/13
Step-by-step explanation:
You have to divide 2352÷6=587
