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erastova [34]
3 years ago
9

Let ∠D be an acute angle such that cosD=0.33. Use a calculator to approximate the measure of ∠D to the nearest tenth of a degree

.
Mathematics
2 answers:
tia_tia [17]3 years ago
6 0

Answer:

.3

Step-by-step explanation:

.33 rounded equals .3

andreyandreev [35.5K]3 years ago
5 0

Answer:

PoInT tHrEe Is ThE aNsWeR

Step-by-step explanation:

.3

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Which of the following sets of integers is listed in descending order?
valentina_108 [34]
Your answer is J. because descending means it’s getting smaller
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3 years ago
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If DF=7x-3 and EG=5x+9, find the value of X
PilotLPTM [1.2K]

Answer:

x=6

Step-by-step explanation:

Using the given measurements of the angles and the lengths of the sides, we can determine that this figure must be a <u>rectangle</u>.

Diagonals of a rectangle are <em>always</em> equivalent/congruent.

We can use this information to set up an equation:

DF=EG\\7x-3=5x+9

Add 3 to both sides:

7x-3+3=5x+9+3\\7x=5x+12

Subtract 5x from both sides:

7x-5x=5x-5x+12\\2x=12

Divide both sides by 2

\frac{2x}{2}=\frac{12}{2}\\x=6

3 0
2 years ago
Place lee's 0.365 and 3.521 on the number line below make sure to label your number line
VARVARA [1.3K]
So 3.521 will come after o.365
3 0
3 years ago
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No Spam. I will mark Brainliest, if you get it right. A tank's length is 4 feet longer than its width. The height is 2 feet more
dmitriy555 [2]

Answer: 3

Step-by-step explanation:

Let say x the width of the tank,

x+4 its length,

x+2 its height

Volume=105=x(x+4)(x+2)\\\\P(x)=x^3+6x^2+8x-105=0\\\\105=3*5*7\\\\P(1)\neq 0\\P(-1)\neq 0\\P(3)=0\\\\\begin{array}{|c|cccc|}&x^3&x^2&x&1\\&1&6&8&-105\\x=3&&3&27&105\\----&--&--&--&--\\&1&9&35&0\\\end{array}\\\\\\P(x)=x^3+6x^2+8x-105=(x-3)(x^2+9x+35)\\And \ x^2+9x+35\ is\ not \ factorizable\ (\Delat=9^2-4*35 < 0)\\

<u>width=3</u>

length=3+4=7

height=3+2=5

4 0
3 years ago
You want to place a towel bar that is 24 1/4 centimeters long in the center of a door that is 70 1/3 centimeters wide. How far s
Aleksandr [31]

Answer:

The towel bar should be placed at a distance of 23\frac{1}{24}\ cm from each edge of the door.

Step-by-step explanation:

Given:

Length of the towel bar = 24\frac14\ cm

Now given length is in mixed fraction we will convert in fraction.

To Convert mixed fraction into fraction Multiply the whole number part by the fraction's denominator, then Add that to the numerator, then write the result on top of the denominator.

24\frac14\ cm can be Rewritten as \frac{97}{4}\ cm

Length of the towel bar =  \frac{97}{4}\ cm

Length of the door = 70 \frac13\ cm

70 \frac13\ cm can be Rewritten as \frac{211}{3}\ cm

Length of the door = \frac{211}{3}\ cm

We need to find the distance bar should be place at from each edge of the door.

Solution:

Let the distance of bar from each edge of the door be 'x'.

 So as we placed the towel bar in the center of the door it divides into two i.e. '2x'

Now we can say that;

\frac{97}{4}+2x=\frac{211}{3}\\\\2x=\frac{211}{3}-\frac{97}{4}

Now we will take LCM to make the denominators common we get;

2x=\frac{211\times4}{3\times4}-\frac{97\times3}{4\times3}\\\\\\2x= \frac{844}{12}+\frac{281}{12}

Now denominators are common so we will solve the numerators.

2x =\frac{844-291}{12}\\\\2x=\frac{553}{12}\\\\x=\frac{553}{12\times2} =\frac{553}{24}

Or x=23\frac{1}{24}\ cm

Hence The towel bar should be placed at a distance of 23\frac{1}{24}\ cm from each edge of the door.

8 0
3 years ago
Read 2 more answers
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