Answer:
If
then
and 
a | b | a + b (answer)
0 | 0 | 0
0 | 1 | 1
0 | 2 | 2
1 | 0 | 1
2 | 0 | 2
1 | 1 | 2
2 | 1 | 3
Step-by-step explanation:
Considering the following conditions for the real numbers:

Following the rules of these in-equations, it is possible to deduce:

Then, if the proposed statement is:

The conditions above shall comply the requirements established, but first, analyzing the statement:
If
and
then
,
and
.
If
and b a non negative real number, then
, but because to
, then
. Due to the commutative property of sums, the same behavior will be presented if
and a a non negative real number.
According to that, if
, then
and
.
Answer:
2. (-3f)
3. (4f)
4. x - 11 (not sure if this one is correct)
Step-by-step explanation:
Move -3 to the left of f = -3f
Move 4 to the left of f = 4f
f(x)=x+11 f ( x ) = x + 11
Answer:
The change to the face 3 affects the value of P(Odd Number)
Step-by-step explanation:
Analysing the question one statement at a time.
Before the face with 3 is loaded to be twice likely to come up.
The sample space is:

And the probability of each is:








P(Odd Number) is then calculated as:


Take LCM



After the face with 3 is loaded to be twice likely to come up.
The sample space becomes:

The probability of each is:








Take LCM


Comparing P(Odd Number) before and after
--- Before
--- After
<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>
Answer:

Step-by-step explanation:
