Original price of the radio is $64.30
Sale price - $51.44
Discount rate - 20%
This means that $51.44 is the discounted price or is equivalent to 80% of the original price, since the 20% equivalent is deducted from the original price.
To get the original price, divide $51.44 by its corresponding percentage, 80%.
$51.44 / 80% = $64.30
To get the discount, multiply the original price by its discount rate
$64.30 x 20% = $12.86
To get the sales price, deduct the discount from the original price.
$64.30 - $12.86 = $51.44
100% - 20% = 80%
Answer:
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Step-by-step explanation:
Answer:
P=0.147
Step-by-step explanation:
As we know 80% of the trucks have good brakes. That means that probability the 1 randomly selected truck has good brakes is P(good brakes)=0.8 . So the probability that 1 randomly selected truck has bad brakes Q(bad brakes)=1-0.8-0.2
We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.
We have to find the probability of each event (9, 10 or 11 trucks from 16 will pass the inspection) . To find the required probability 3 mentioned probabilitie have to be summarized.
So P(9/16 )= C16 9 * P(good brakes)^9*Q(bad brakes)^7
P(9/16 )= 16!/9!/7!*0.8^9*0.2^7= 11*13*5*16*0.8^9*0.2^7=approx 0.02
P(10/16)=16!/10!/6!*0.8^10*0.2^6=11*13*7*0.8^10*0.2^6=approx 0.007
P(11/16)=16!/11!/5!*0.8^11*0.2^5=13*21*16*0.8^11*0.2^5=approx 0.12
P(9≤x<12)=P(9/16)+P(10/16)+P(11/16)=0.02+0.007+0.12=0.147
100
6738 —> 7000
5903 —> 6000
7000 - 6000 = 1000
We are tasked to solve for the number of ways the 8 students be competing for the 1st, 2nd, 3rd, 4th voilin chair in the schools orchestra. The number of ways if can only be filled is though the formula used in number counting, that is
8x7x6x5
Therefore, there are 1680 ways
