Hello and Good Morning/Afternoon
<u>Let's take this problem step-by-step</u>:
<u>To find the solution to a system of equation</u>
⇒ <em>must set</em> the equations equal to each other
⇒ and solve
<u>Let's put that into action</u>
- At this point, to make the whole thing equal zero
⇒ either 'x+3' or 'x-3' equals zero
⇒ must find 'x' that satisify either equation
<u>Let's find the corresponding f(x) to each x-value</u>
<u>Therefore the solutions are (3,6) and (-3,18)</u>
<u />
<u>Answer: (3,6), (-3,18)</u>
<u></u>
Hope that helps!
#LearnwithBrainly
Answer:
YASSSSSSSS
Step-by-step explanation:
Hi There! :)
<span>Calculate the area of the circular field if its radius is 110m and express this area in hectares?
</span>A≈38013.27<span>m²
</span><span>
</span>
Answer:
one , i guess....
because the conjecture is only true if it satisfies all the cases.
Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:
First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;
Divide by m to isolate 
.
To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
