All categories

3 years ago

If angle x=55% and angle y=35, calculate the following 1.cos(x+y)

Mathematics

1 answer:

Setler79 [48]3 years ago

4 0

Answer:

cos(X+Y) = cos(55+35) = cos(90) = 0

Step-by-step explanation:

cos(X+Y) = cosXcosY - sinXsinY

cos(55+35) = cos(55)cos(35) - sin(55)sin(35)

cos(55+35) = cos(55)cos(35) - cos(90-55)cos(90-35)

cos(55+35) = cos(55)cos(35) - cos(35)cos(55)

cos(55+35) = 0

cos(90) = 0

You might be interested in

How do I find the answer?

Veronika [31]

Answer:

ans is nothing

plz its is a jock

4 0

3 years ago

Neuma had a container that held of a kilogram of rainbow sprinkles. She divided the sprinkles evenly to put on top of the 9 serv

ladessa [460]

Answer:

Neuma should have only divided 9 by 9, not 54 by 9

Step-by-step explanation:

i hope it helps and is correct

6 0

3 years ago

Read 2 more answers

Without performing the calculation, estimate which expression is larger. Explain how you know

Naddik [55]

Answer:

4 × 10¹⁰ > 2 × 10⁵

Step-by-step explanation:

Given that,

Two numbers in scientific notation.

First number: 4 × 10¹⁰

Second number: 2 × 10⁵

To compare scientific notation number.

First check the exponent of 10

If exponent is larger then number becomes larger.

First number exponent is 10 and second number exponent if 5

10 > 5

Therefore,

4 × 10¹⁰ > 2 × 10⁵

6 0

3 years ago

Irma has 5/6 yard of ribbon. She cuts it into 1/6 yard pieces.How many pieces of ribbon does she have

Aleksandr-060686 [28]

Answer: 1? idk use google :)

Step-by-step explanation:

3 0

3 years ago

Determine the function which corresponds to the given graph. (3 points)

damaskus [11]

Answer:

The center of the circle is c=50 and radius of the circle is $r=\sqrt{3}$

Step-by-step explanation:

Given circle equation is

$x^2-4x+y^2+14y=-50\hfill(1)$

Equation (1) can be written as $x^2-4x+y^2+14y+50=0\hfill(2)$

we know that the equation of the circle is of the form

$x^2+y^2+2gx+2fy+c=0\hfill(3)$

with centre (-g,-f) and radius= $\sqrt{g^2+f^2-c}$

when, g,f and c are constants

Now comparing the (2) and (3) equations we get 2g=-4

$g=\frac{-4}{2}$

$g=-2$

$2fy=14$

$f=\frac{14}{2}$

$f=7$

and $c=50$

Now to find the centre and radius of the given circle equation, substituting the values of g,f,c in the formulae of centre and radius

centre=(-g,-f)

=(-(-2),-7)

centre=(2,7)

Radius= $\sqrt{g^2+f^2-c}$

= $\sqrt{(-2)^2+(7)^2-50}$

= $\sqrt{4+49-50}$

= $53-50$

Radius= $\srqt{3}$

The center of the circle is c=50 and the radius of the circle equation $r=\sqrt{3}$

6 0

3 years ago

If angle x=55% and angle y=35, calculate the following 1.cos(x+y) ​

If angle x=55% and angle y=35, calculate the following 1.cos(x+y)