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nlexa [21]
3 years ago
15

Of the 3 primary electrical entites (voltage, current, and resistance )which is the result of the other two

Computers and Technology
1 answer:
sveta [45]3 years ago
5 0

Answer: A

Explanation:cuz

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Write a program that reads a list of integers into a list as long as the integers are greater than zero, then outputs the smalle
almond37 [142]

Answer:

Check the explanation

Explanation:

10

5

3

21

2

-6

the output will be somthing like this:

2 21

You can then suppose that the list of integers will contain at least 2 values.

4 0
3 years ago
Construct a class that will model a quadratic expression (ax^2 + bx + c). In addition to a constructor creating a quadratic expr
stich3 [128]

Answer:

Following are the code to this question:

#include <iostream>//header file

#include<math.h>//header file

using namespace std;

class Quadratic//defining a class Quadratic  

{

private:

double a,b,c;//defining a double variable

public:

Quadratic()//defining default constructor

{

a = 0;//assigning value 0  

b = 0;//assigning value 0  

c = 0;//assigning value 0  

}

Quadratic(double a, double b, double c)//defining a parameterized constructor  

{

this->a = a;//use this keyword to hold value in a variable

this->b = b;//use this keyword to hold value in b variable

this->c = c;//use this keyword to hold value in c variable

}

double getA() //defining a get method  

{

return a;//return value a

}

void setA(double a)//defining a set method to hold value in parameter

{

this->a = a;//assigning value in a variable

}

double getB() //defining a get method  

{

return b;//return value b

}

void setB(double b)//defining a set method to hold value in parameter  

{

this->b = b;//assigning value in b variable

}

double getC() //defining a get method

{

return c;//return value c

}

void setC(double c)//defining a set method to hold value in parameter

{

this->c = c;//assigning value in c variable

}

double Evaluate(double x)//defining a method Evaluate to hold value in parameter

{

return ((a*x*x)+(b*x)+c);//return evaluated value

}

double numberOfReal()//defining a method numberOfReal to calculates the real roots

{

return (b*b)-(4*a*c);//return real roots

}

void findroots()//defining a method findroots

{

double d=numberOfReal();//defining double variable to hold numberOfReal method value

if(d<0)//use if block to check value of d less than 0

cout<<"Equation has no real roots"<<endl;//print message

else

{

double r1=(-b+sqrt(numberOfReal()))/(2*a);//holding root value r1

double r2=(-b-sqrt(numberOfReal()))/(2*a);//holding root value r2

if(r1==r2)//defining if block to check r1 equal to r2

cout<<"Equation has one real root that is "<<r1<<endl;//print message with value

else//else block

cout<<"The equation has two real roots that are "<<r1<<" and "<<r2<<endl;////print message with value

}

}

void print()//defining a method print  

{

cout<< a << "x^2 + " << b << "x + " << c <<endl;//print Quadratic equation

}

};

int main()//defining main method  

{

Quadratic q(5,6,1);//creating Quadratic class object that calls parameterized constructor

q.print();//calling print method

cout<<q.numberOfReal()<<endl;//calling method numberOfReal that prints its value

q.findroots();//calling method findroots

cout<<q.Evaluate(-1);//calling method Evaluate that prints its value

return 0;

}

Output:

5x^2 + 6x + 1

16

The equation has two real roots that are -0.2 and -1

0

Explanation:

In the above code, a class "Quadratic" is declared, which is used to define a default and parameter constructor to holds its parameter value.

In the next step, the get and set method is defined that holds and returns the quadratic value, and "Evaluate, numberOfReal, findroots, and print" in the evaluate method a double variable is used as a parameter that returns evaluated value.

In the "numberOfReal" method it calculates the real roots and returns its value. In the "findroots" method a double variable "d" is declared that hold "numberOfReal" value,

and use a conditional statement to check its value, and in the print method, it prints the quadratic equation.

In the main method, the lass object it calls the parameterized constructor and other methods.

5 0
3 years ago
How can you use the Address Book to address an email message? Use the drop-down menus to complete the sentences. 1. Type an emai
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Answer:

1. AutoCorrect

2. Address book

Explanation:

stan bts ?

5 0
3 years ago
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Question: <em>How would I copy this image?</em>

Answer: Either screenshot it, or CTRL C ± CTRL V it. To screenshot something, open 'snipping tool' and pull up the PDF, then box in whatever you are trying to copy. You can also reverse image search it to find it somewhere on the web.

Uplifting Note: To you, smiling at someone may mean nothing, but to them, it might be their whole world.

3 0
3 years ago
Why is image compression an important part of vidoetechnology?
OLEGan [10]

Answer: Image compression is the technique which is responsible for the reduction in the size of the image according to the need of the video technology. Image compression is done because of the following reasons:-

  • Makes more space for the storage and creates space.
  • It also reduces the time that is used up for the uploading of the video through internet.
  • Text, labels etc might also be needed to inserted along with the image .

4 0
3 years ago
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