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Elden [556K]
4 years ago
15

An observer (O) spots a plane flying at a 55° angle to his horizontal line of sight. If the plane is flying at an altitude of 21

,000 ft., what is the distance (x) from the plane (P) to the observer (O)? A. 20,793 feet B. 25,636 feet C. 28,793 feet D. 36,585 feet

Mathematics
2 answers:
xz_007 [3.2K]4 years ago
3 0

Answer:

<em>B. 25,636 feet</em>

Step-by-step explanation:

sin(55) = h/x

h = 21,000

sin(55) = 21,000/x

x = 21,000/sin(55)

x = 25636.27 ≈ 25,636 feet

Hope this helped! :)

Goshia [24]4 years ago
3 0

Answer:

B. 25,636

Step-by-step explanation:

In this example we will us the sin.

sin55=21000/x

multiply both sides by x

sin55(x)=21000

the sin of 55 degrees is around 0.81915 so we can substitute that number

0.81915x=21000

divide both sides by 0.81915

x≈25636.3303424

we can then round this number to get:

answer choice B 25636

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