An observer (O) spots a plane flying at a 55° angle to his horizontal line of sight. If the plane is flying at an altitude of 21
,000 ft., what is the distance (x) from the plane (P) to the observer (O)? A. 20,793 feet B. 25,636 feet C. 28,793 feet D. 36,585 feet
2 answers:
Answer:
<em>B. 25,636 feet</em>
Step-by-step explanation:
sin(55) = h/x
h = 21,000
sin(55) = 21,000/x
x = 21,000/sin(55)
x = 25636.27 ≈ 25,636 feet
Hope this helped! :)
Answer:
B. 25,636
Step-by-step explanation:
In this example we will us the sin.
sin55=21000/x
multiply both sides by x
sin55(x)=21000
the sin of 55 degrees is around 0.81915 so we can substitute that number
0.81915x=21000
divide both sides by 0.81915
x≈25636.3303424
we can then round this number to get:
answer choice B 25636
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