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Nikolay [14]
3 years ago
5

Determine the number of solutions of this equation.

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
5 0

Answer:

C, For every x in the real numbers

Step-by-step explanation:

x - 2x + 12 + x - 12 = 0

x - 2x + x = 0

0=0, For every x!

notka56 [123]3 years ago
3 0
C.) infinitely many solutions.

Given the equation, x - 2(x -6) = -x + 12:

x - 2(x -6) = -x + 12

Distribute -2 into the terms inside the parenthesis:

x - 2(x -6) = -x + 12

x - 2x + 12 = -x + 12

Combine like terms:

-x + 12 = - x + 12

Subtract 12 from both sides:

-x + 12 - 12 = - x + 12 - 12

- x = - x

Add x to both sides:

- x + x = - x + x

0 = 0 (true statement).

This means that any value of x will satisfy the equation, thereby making it infinitely many solutions.

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Chris Christina collects stamps she is 47 stamps and all she has 20 from Europe the number of African stamps is 2 times the numb
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Answer:

Step-by-step explanation:

Let x represent the number of stamps from Europe.

Let y represent the number of stamps from Africa.

Let z represent the number of stamps from Asia.

She has 47 stamps in all. This means that

x + y + z = 47 - - - - - - - - - - - 1

The number of African stamps is 2 times the number of Asian stamps. This means that

y = 2z

She has 20 stamps from Europe. Therefore, substituting x = 20 and y = 2z into equation 1, it becomes

20 + 2z + z = 47

3z = 47 - 20 = 27

z = 27/3 = 9

y = 2z = 2 × 9

y = 18

She has 20 stamps from Europe, 18 stamps from Africa and 9 stamps Asia.

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3 years ago
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Oksanka [162]
X² + 11x - 26 = 0
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Jimmy successfully factors a quadratic $4x^2 + bx + c$ as \[4x^2 + bx + c = (Ax + B)(Cx + D),\]where $A,$ $B,$ $C,$ and $D$ are
saul85 [17]

Answer:

±1, ±2, and ±4

Step-by-step explanation:

4x² + bx + c = (Ax + B) (Cx + D)

Distribute:

4x² + bx + c = ACx² + (AD + BC) x + BD

Matching the coefficients, AC = 4.  So A must be a factor of 4.  Possible values of A are therefore ±1, ±2, and ±4.

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