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postnew [5]
2 years ago
9

Suppose that 30% of all houses need a paint job. Also, 15% of all houses need both a paint job and a new roof. Further, 7% of al

l houses that need a new roof also need new windows. what is the probability that a randomly selectede house needs a new window?
Mathematics
1 answer:
ivann1987 [24]2 years ago
8 0

Answer:

0.0105

Step-by-step explanation:

given that 30% of all houses need a paint job. Also, 15% of all houses need both a paint job and a new roof. Further, 7% of all houses that need a new roof also need new windows.

If total houses are 100, then 30 require a paint along.  15 require both paint and new roof.

Out of 15 houses which require new roof 7% need new windows

i.e. no of houses which need new windows = 15*7%\\=1.05

If there are total 100 houses, 1.05 houses require a new window

So probability that a randomly selectede house needs a new window

= 0.0105

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Please answer this correctly
GREYUIT [131]

Answer:

$8.82

Step-by-step explanation:

4.6 (1.15) + 0.5 (1.12) + 2.25 (1.32)

5.29 + 0.56 + 2.97

8.82

8 0
3 years ago
Josh can paint a whole room in m hours while Kevin can paint a whole room in n hours. How many parts of the room can they paint
Leona [35]
<h3>Answer: (m+n)/(mn)</h3>

Work Shown:

Josh:

1 room = m hours

1/m room = 1 hour

Kevin:

1 room = n hours

1/n room = 1 hour

We see that the rates for Josh and Kevin are 1/m and 1/n respectively. This is the amount of a room they paint in one hour. Combine the fractions

1/m + 1/n = n/(mn) + m/(mn) = (n+m)/(mn) = (m+n)/(mn)

The expression (m+n)/(mn) represents how much of the room they get painted in 1 hour. This is if they work together and it assumes neither worker slows the other one down.

7 0
3 years ago
Factor each polynomial. Look for a GCF first
weeeeeb [17]

Answer:

20. x\left(x-6\right)\left(x+8\right)

22. 2\left(x+1\right)\left(x+4\right)

24. 5m\left(m-1\right)\left(m+7\right)

Step-by-step explanation:

20. x^3+2x^{2} -48x

The GCF is x, so you group it out of the equation first.

x(x^{2} +2x-48)

Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.

?+?=2\\?*?=-48

The two numbers would be -6 and 8. You then differentiate the squares.

x\left(x-6\right)\left(x+8\right)

22. 2x^{2} +10x+8

The GCF is 2, so you must group it out.

2(x^{2} +5x+4)

Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.

?+?=5\\?*?=4

The two numbers would be 1 and 4. Finally, differentiate the squares.

2\left(x+1\right)\left(x+4\right)

24. 5m^{3} +30m^2-35m

The GCF is 5m, so you must group it out.

5m(m^2+6m-7)

Find the two numbers that will equal to 6 when you add them and will equal to -7 when you multiply them.

?+?=6\\?*?=-7

The two numbers would be -1 and 7. Finally, differentiate the squares.

5m\left(m-1\right)\left(m+7\right)

7 0
2 years ago
I’ll give brainleyyyyyyy
Ira Lisetskai [31]

Answer:

0, -2, 2, -1

Step-by-step explanation:

You are trying to make it so that the one of the (  )= 0.

An example is (x+15) or (2x+3)

the first l one would be x= -15 since -15+15 would equal 0.

The second one is -3/2 since it would be -3+3 which would equal 0.

also since the equation starts with x( or -x it doesn't really matter) one of the zeros would also be 0.

Hope this helps!

7 0
2 years ago
HELP ME !?!!!!?!?? Please
vovikov84 [41]

Answer:

Step-by-step explanation:i havent done something like this in a long time

7 0
3 years ago
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