ΔABC is a right triangle in which angle B is a right angle, AB = 1, AC = 2, and BC = square root of 3 . cos C × sin A equals wha
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1 answer:
Remark
Study the triangle carefully. It may not be exactly as you have drawn it, but it will work if you just follow the givens.
Givens
AC = 2
AB = 1
BC = sqrt(3)
Step One
Find Cos C
Cos(C) = adjacent / Hypotenuse
Cos(C) = BC / AB
Cos(C) = sqrt(3)/2
Step Two
Find Sin(A)
Sin(A) = opposite / hypotenuse
Sin(A) = AB / AC
Sin(A) = 1/2
Step Three
Find Cos(C) * Sin(A)
Cos(C) * Sin(A) = sqrt(3)/2 * 1/2 = sqrt(3) / 4 <<<< Answer
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Answer:
-15
Step-by-step explanation:
Given is a polynomial in x
We have to find the remainder when the above polynomial is divided by x+5
Remainder theorem says that f(x) gives remainder R when divided by polynomial x-a means f(a) = R
Applying the above theorem we can say that value of the function when x =-5
= Remainder when f is divided by x+5
= F(-5)
Substitute the value of -5 in place of x
= (-5)^4 + 12(-5)^3 + 30(-5)^2 - 12(-5) + 70
= 625-1500+750+60+70
= 5
Hence answer is 5