Solve the inequality and enter your solution as an inequality in the box below.

When the population mean and standard deviation are known, what distribution is used for the analysis of the sample?.

Kitty [74]

When the population mean and standard deviation are known, you use the standard normal distribution

<h3>How to determine the distribution?</h3>

There are several probability distributions; these include

Normal distribution
Poisson distribution
Chi square distribution
Binomial distribution
Etc

Of all these distribution, only the standard normal distribution can be used when the population mean and standard deviation are known,

Note that it is also referred to as the z-distribution

Read more about probability distributions at:

brainly.com/question/24756209

7 0

2 years ago

Which equation could you use to solve for x in the proportion StartFraction 4 over 5 EndFraction = StartFraction 9 over x EndFra

Rudik [331]

Answer:

(b) 4 x = 4 5 is the needed expression to solve for the value of x.

Step-by-step explanation:

Here, the given proportion is simplified as:

$\frac{4}{5} = \frac{9}{x}$

Now, to simplify any proportion of the form $\frac{a}{b} = \frac{c}{d}$ the simplest way is CROSS MULTIPLICATION.

So, cross multiplying $\frac{a}{b} = \frac{c}{d} \implies ad = bc$

Similarly cross multiplying $\frac{4}{5} = \frac{9}{x}$ , we get:

4 (x) = (9) (5)

or, 4 x = 45

Hence, 4 x = 45 is the needed expression to solve for the value of x.

4 0

3 years ago

Read 2 more answers

The graph of the continuous function g, the derivative of the function f, is shown above. The function g is piecewise linear for

4vir4ik [10]

A) $g=f'$ is continuous, so $f$ is also continuous. This means if we were to integrate $g$ , the same constant of integration would apply across its entire domain. Over $0$ , we have $g(x)=2x$ . This means that

$f_{0$

For $f$ to be continuous, we need the limit as $x\to1^-$ to match $f(1)=3$ . This means we must have

$\displaystyle\lim_{x\to1}x^2+C=1+C=3\implies C=2$

Now, over $x$ , we have $g(x)=-3$ , so $f_{x$ , which means $f(-5)=17$ .

b) Integrating over [1, 3] is easy; it's just the area of a 2x2 square. So,

$\displaystyle\int_1^6g(x)=4+\int_3^62(x-4)^2\,\mathrm dx=4+6=10$

c) $f$ is increasing when $f'=g>0$ , and concave upward when $f''=g'>0$ , i.e. when $g$ is also increasing.

We have $g>0$ over the intervals $0$ and $x>4$ . We can additionally see that $g'>0$ only on $0$ and $x>4$ .

d) Inflection points occur when $f''=g'=0$ , and at such a point, to either side the sign of the second derivative $f''=g'$ changes. We see this happening at $x=4$ , for which $g'=0$ , and to the left of $x=4$ we have $g$ decreasing, then increasing along the other side.

We also have $g'=0$ along the interval $-1$ , but even if we were to allow an entire interval as a "site of inflection", we can see that $g'>0$ to either side, so concavity would not change.

5 0

3 years ago

Ayden had a goal of finishing painting at least 80% of the 500 square meters of a houses walls by today. He finishes 415 meters

lord [1]

Yes no square meters less 15 more

3 0

3 years ago

A 4500 square foot roll of plastic wrap costs $23.95. If 120 square feet is need for a party game, what is the monetary value of

nadya68 [22]

For this case, the first thing to do is define a variable.

We have then: