Answer:
Step-by-step explanation:
<h3>Part B</h3>
Assumed the dimensions of the top and bottom parts are identical.
Since the cylindrical part has total height of 1.8 cm and the hemisphere volume is transferred to bottom part and the cone part is still full, the value of h is the difference of the total height of cylinder and full part of the top section of cylinder:
- h = 1.8 cm - 0.3 cm = 1.5 cm
<h3>Part C</h3>
Find the volume of sand in the bottom part. It consists of a hemisphere and a cylinder of 1.5 cm height.
- V(cylinder) = πr²h = 3.14*(2.6/2)²*1.5 ≈ 7.96 cm³
- V(hemisphere) = 2/3πr³ = 2/3*3.14*(2.6/2)³ ≈ 4.6 cm³
<u>Total sand in the bottom part:</u>
<u>Time taken:</u>
- 12.56 / 0.05 = 251.2 seconds = 4 min 11.2 seconds
Step-by-step explanation:
6a.


6b.



Answer:
Step-by-step explanation:
I see you're in college math, so we'll solve this with calculus, since it's the easiest way anyway.
The position equation is
That equation will give us the height of the rock at ANY TIME during its travels. I could find the height at 2 seconds by plugging in a 2 for t; I could find the height at 12 seconds by plugging in a 12 for t, etc.
The first derivative of position is velocity:
v(t) = -3.72t + 15 and you stated that the rock will be at its max height when the velocity is 0, so we plug in a 0 for v(t):
0 = -3.72t + 15 and solve for t:\
-15 = -3.72t so
t = 4.03 seconds. This is how long it takes to get to its max height. Knowing that, we can plug 4.03 seconds into the position equation to find the height at 4.03 seconds:
s(4.03) = -1.86(4.03)² + 15(4.03) so
s(4.03) = 30.2 meters.
Calculus is amazing. Much easier than most methods to solve problems like this.
Answer:
20 + (-35)
Step-by-step explanation:
(-20) + 10 = -10
20 + (-35) = -15