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Vera_Pavlovna [14]
3 years ago
10

An orange juice company sells a can of frozen orange juice that measures 9.4 centimeters in height and 5.2 centimeters in diamet

er. The company wants to sell a larger can of juice. The height of the can is kept at 9.4 cm, but the diameter is increased to 8.5 cm. About how many times more juice will the new can hold?
Image is the same question w/ a model.

Mathematics
1 answer:
drek231 [11]3 years ago
3 0
<h2>Hello!</h2>

The answer is:

The third option:

2.7 times as much.

<h2>Why?</h2>

To calculate how many more juice will the new can hold, we need to calculate the old can volume to the new can volume.

So, calculating we have:

Old can:

Since the cans have a right cylinder shape, we can calculate their volume using the following formula:

Volume_{RightCylinder}=Volume_{Can}=\pi r^{2} h

Where,

r=radius=\frac{diameter}{2}\\h=height

We are given the old can dimensions:

radius=\frac{5.2cm}{2}=2.6cm\\\\height=9.4cm

So, calculating the volume, we have:

Volume_{Can}=\pi *2.6cm^{2} *9.4cm=199.7cm^{3}

We have that the volume of the old can is:

Volume_{Can}=199.7cm^{2}

New can:

We are given the new can dimensions, the diameter is increased but the height is the same, so:

radius=\frac{8.5cm}{2}=4.25cm\\\\height=9.4cm

Calculating we have:

Volume_{Can}=\pi *4.25cm^{2} *9.4cm=533.40cm^{3}

Now, dividing the volume of the new can by the old can volume to know how many times more juice will the new can hold, we have:

\frac{533.4cm^{3} }{199.7cm^{3}}=2.67=2.7

Hence, we have that the new can hold 2.7 more juice than the old can, so, the answer is the third option:

2.7 times as much.

Have a nice day!

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suppose the annual rate of inflation average 3.8% over the next 10 years. the present cost of oil change for tour car is $23.95.
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what we know:

The cost changed in 10 years to 23.95

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2 years ago
SAT scores have a mean of 1026 and a standard deviation of 209. ACT scores have a mean of 20.8 and a standard deviation of 4.8.
Y_Kistochka [10]

Answer:

The z-score for SAT exam of junior is much small than his ACT score. This means he performed well in his ACT exam and performed poor in his SAT exam.

Step-by-step explanation:

Mean SAT scores = 1026

Standard Deviation = 209

Mean ACT score = 20.8

Standard Deviation = 4.8

We are given SAT and ACT scores of a student and we have to compare them. We cannot compare them directly so we have to Normalize them i.e. convert them into such a form that we can compare the numbers in a meaningful manner. The best way out is to convert both the values into their equivalent z-scores and then do the comparison. Comparison of equivalent z-scores will tell us which score is higher and which is lower.

The formula to calculate the z-score is:

z=\frac{x-\mu}{\sigma}

Here, μ is the mean and σ is the standard deviation. x is the value we want to convert to z score.

z-score for junior scoring 860 in SAT exam will be:

z=\frac{860-1026}{209}=-7.59

z-score for junior scoring 16 in ACT exam will be:

z=\frac{16-20.8}{4.8}=-1

The z-score for SAT exam of junior is much small than his ACT score. This means he performed well in his ACT exam and performed poor in his SAT exam.

4 0
3 years ago
Vectors: Find the vector from the point A=(−1,−7,3) to the point B=(3,−2,9).
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Answer:

\overrightarrow {AB} = (4,5,6)

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

Step-by-step explanation:

The vector AB is the vectorial difference between point A and B, that is:

\overrightarrow {AB} = \vec B - \vec A

Given that \vec A = (-1,-7,3) and \vec B = (3,-2,9), the vector AB is:

\overrightarrow {AB} = (3,-2,9)-(-1,-7,3)

\overrightarrow{AB} = (3-(-1),-2-(-7),9-3)

\overrightarrow {AB} = (4,5,6)

The vectorial equation of the line is represented by:

\langle x, y, z\rangle = \vec A + t \cdot \overrightarrow {AB}

Where t is the parametric variable, dimensionless. Given that \vec A = (-1,-7,3) and \overrightarrow {AB} = (4,5,6)

\langle x,y,z \rangle = \langle -1,-7,3 \rangle + t\cdot \langle 4,5,6 \rangle

Finally, the list of questions are now checked:

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

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Answer:

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now 4=2n so n=2

now k=1

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7 0
3 years ago
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