Problem One
Call the radius of the second can = r
Call the height of the second can = h
Then the radius of the first can = 1/3 r
The height of the first can = 3*h
A1 / A2 = (2*pi*(1/3r)*(3h)] / [2*pi * r * h]
Here's what will cancel. The twos on the right will cancel. The 3 and 1/3 will multiply to one. The 2 r's will cancel. The h's will cancel. Finally, the pis will cancel
Result A1 / A2 = 1/1
The labels will be shaped differently, but they will occupy the same area.
Problem Two
It seems like the writer of the problem put some lids on the new solid that were not implied by the question.
If I understand the problem correctly, looking at it from the top you are sweeping out a circle for the lid on top and bottom, plus the center core of the cylinder.
One lid would be pi r^2 = pi w^2 and so 2 of them would be 2 pi w^2
The region between the lids would be 2 pi r h for the surface area which is 2pi w h
Put the 2 regions together and you get
Area = 2 pi w^2 + 2 pi w h
Answer: Upper left corner <<<<< Answer
Answer: 144
Step-by-step explanation:
Not me but I do go to somewhere is spring where are y’all?
Based on the given information, let x represent the grade for the fifth quiz.
(79+88+95+71+x)/5=85
(333+x)/5=85
333+x=425
x=92
Jackson would have to earn a 92 on his fifth quiz to earn an average of 85.
Answer:
Hi, There! my name is Jay and I'm here to help!
<h2>Question</h2>
Find the number that makes the ratio equivalent to 2:7
<h2>Answer</h2>
4:14, 6:21, 8:28
Step-by-step explanation:
Ratios that are equal to each other are called equivalent ratios. You can find an equivalent ratio by multiplying or dividing each term of a ratio by the same number.
Therefore, I Hope this helps!
Take Care!
Happy Veterans day!
