The first three terms of the sequence defined by the recursive formula are 2, -7/2 and -3/2
Given:

where,
n = number of terms
First term, a1 = 2
Second term, a2

a2 = {(2 - 1)/ 4} - 2
= 1/4 - 2
= (1-8) / 4
= - 7/4
Third term, a3
= {(3-1) / 4} - 2
= 2/4 - 2
= 1/2 - 2
= (1-4) / 2
= -3/2
Therefore, the first three terms of the sequence defined by the recursive formula are 2, -7/2 and -3/2
Learn more about sequence:
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This is one of the photos I used to answer, I’m going to send the second one
Hai !
6x+7+x^2+2x^2-3
6x+7+x^2+2x^2+-3
combine like terms
6x+7+x^2+2x^2+-3
(x^2+2x^2)+(6x)+(7+-3)
=3x^2+6x+4
Cheers :3
Answer: D: Half turn about the origin
<span>94.25 centimeters is your answer. Hope this helps!</span>