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3 years ago

The two sets of data below show the number of bubbles blown in fifty trials using two different bubble solutions.

Mathematics

2 answers:

storchak [24]3 years ago

5 0

Answer:

Step-by-step explanation:

i got it right

frosja888 [35]3 years ago

3 0

Answer:

the median, because it decreases the influence of outliers

Step-by-step explanation:

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What is 0.5333333333 as a fraction

Inga [223]

$x=0.5\overline{3}\\
10x=5.\overline{3}\\
100x=53.\overline{3}\\
100x-10x=53.\overline{3}-5.\overline{3}\\
90x=48\\
x=\dfrac{48}{90}=\dfrac{8}{15}$

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3 years ago

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What is the value of x in equation (-35)^x = 1

FinnZ [79.3K]

Answer:

x = 0.

Step-by-step explanation:

(-35)^x = 1

Now any number to the power 0 is 1.

So x = 0.

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STALIN [3.7K]

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3 years ago

If x = a cosθ and y = b sinθ , find second derivative

Olin [163]

I'm guessing the second derivative is for y with respect to x, i.e.

$\dfrac{\mathrm d^2y}{\mathrm dx^2}$

Compute the first derivative. By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$y=b\sin\theta\implies\dfrac{\mathrm dy}{\mathrm d\theta}=b\cos\theta$

$x=a\cos\theta\implies\dfrac{\mathrm dx}{\mathrm d\theta}=-a\sin\theta$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{b\cos\theta}{-a\sin\theta}=-\dfrac ba\cot\theta$

Now compute the second derivative. Notice that $\frac{\mathrm dy}{\mathrm dx}$ is a function of $\theta$ ; so denote it by $f(\theta)$ . Then

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm dx}$

By the chain rule,

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm df}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$