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Eddi Din [679]
3 years ago
13

If the regular price is $28 and the sales price is $21, what is the percent of the discount

Mathematics
2 answers:
ad-work [718]3 years ago
6 0
So the answer is seven cause u mines twenty eight and twenty one and the answer is seven
lorasvet [3.4K]3 years ago
5 0

Answer:

25%

Step-by-step explanation:

The price dropped by $7, because $28-$21=$7.

7/28 is 1/4. 1/4 in a percentage is 25%, because 1/4=25/100

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Help with algebra problem
dem82 [27]

Answer:

Yes

Step-by-step explanation:

To find the answer, you just have to plug the (x,y) values into the equation to see if it is true.

3(1) > 5(-6) -12

3 > -30 -12

3 > -42

Since 3 > -42 the ordered pair is a solution to the inequality

3 0
3 years ago
Need to keep cell bill under 60.,monthly charge is 30. And texts are 0.05 each. Write an inequality to represent the # of texts
nignag [31]

Answer:

30 + 0.05x < 60

The number of texts she can have is less than 600.

Step-by-step explanation:

Total monthly charge

30 + 0.05 for each text.

So, for x tests, the charge is:

C(x) = 30 + 0.05x

Write an inequality to represent the # of texts she can have?

It has to be under 60, so:

C(x) < 60

30 + 0.05x < 60

The solution is:

0.05x < 30

x < \frac{30}{0.05}

x < 600

The number of texts she can have is less than 600.

5 0
3 years ago
Please help I’ll mark you as brainliest if correct!
Pavlova-9 [17]

Answer:

3 ways

36÷6=6

36÷2=18

36÷3=12

maybe if not then 2 or 4

6 0
2 years ago
Read 2 more answers
HELP ME PLEASE I NEED HELP
eduard

Answer:

sorry dont know

Step-by-step explanation:

6 0
3 years ago
Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





8 0
3 years ago
Read 2 more answers
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