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Fed [463]
3 years ago
6

Can someone please answer this problem and the other I posted previously

Mathematics
1 answer:
pshichka [43]3 years ago
5 0
\cfrac{ \sqrt[4]{9} \sqrt{9}  }{ \sqrt[4]{9^5} } = \cfrac{ \sqrt[4]{9} \sqrt{9}  }{ 9\sqrt[4]{9} } = \cfrac{ \sqrt{9}  }{ 9 } = \cfrac{9^{ \frac{1}{2} }}{9}=9^{ \frac{1}{2}-1 }=9^{- \frac{1}{2} }
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