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3 years ago

8

Reflect the given triangle over the line y=x.

2 answers:

yulyashka [42]3 years ago

7 0

Answer is 3 I think check if it is right x

DaniilM [7]3 years ago

6 0

Answer:

3

Step-by-step explanation:

This task is about reflecting the numbers you have given. So if you had 3 and -3 in the first point, the second one is -3 and 3, following 6 and 3 is reflecting 3 and 6. Finally 3 and 3 reflection is 3 and 3 :)

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A bag contains 14 red marbles and 6 blue marbles. two marbles are randomly drawn without replacement. find the probability that

Ksenya-84 [330]

We take 2 marbles from 20 marbles and the total ways is 20x19:2=190
But we need only 2 red marbles and the ways is 14x13:2=91
And finally we do the division 91:190=91/190 is the probability we need

7 0

3 years ago

What is the square root of -1?<br> -j.<br> -1

Sindrei [870]

Answer:

Its not a real number for the square roots of negative number

its not possible... $\sqrt{-4}$ = -2 x -2 no... 2 x 2 no..... -2 x 2 yea but thats not square root anymore...

Step-by-step explanation:

Give me brainliest!!!

7 0

3 years ago

The circle below is centered at (3, 1) and has a radius of 2. What is its<br> equation?

MissTica

Answer:

( x-3) ^2 + ( y-1) ^2 = 4

Step-by-step explanation:

The equation for a circle is given by

( x-h)^2 + ( y-k) ^2 = r^2 where (h,k) is the center and r is the radius

( x-3) ^2 + ( y-1) ^2 = 2^2

( x-3) ^2 + ( y-1) ^2 = 4

5 0

1 year ago

A cone has a height of 15 yards and a diameter of 10 uarsd what size the volume use pi and round to the nearest hundredth

dsp73

Volume is 392.7 yards cubed

8 0

2 years ago

Read 2 more answers

Verify a(b-c)=ab-ac for a=1.6;b=1/-2;& c=-5/-7

harina [27]

Given:

$a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}$

To verify:

$a(b-c)=ab-ac$ for the given values.

Solution:

We have,

$a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}$

We need to verify $a(b-c)=ab-ac$ .

Taking left hand side, we get

$a(b-c)=1.6\left(\dfrac{1}{-2}-\dfrac{-5}{-7}\right)$

$a(b-c)=1.6\left(-\dfrac{1}{2}-\dfrac{5}{7}\right)$

Taking LCM, we get

$a(b-c)=1.6\left(\dfrac{-7-10}{14}\right)$

$a(b-c)=\dfrac{16}{10}\left(\dfrac{-17}{14}\right)$

$a(b-c)=\dfrac{8}{5}\left(\dfrac{-17}{14}\right)$

$a(b-c)=-\dfrac{68}{35}\right)$

Taking right hand side, we get

$ab-ac=1.6\times \dfrac{1}{-2}-1.6\times \dfrac{-5}{-7}$

$ab-ac=-\dfrac{16}{20}-\dfrac{8}{7}$

$ab-ac=-\dfrac{4}{5}-\dfrac{8}{7}$

Taking LCM, we get

$ab-ac=\dfrac{-28-40}{35}$

$ab-ac=\dfrac{-68}{35}$

Now,

$LHS=RHS$

Hence proved.

7 0

2 years ago