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3 years ago

How to find the area of irregular figures

1 answer:

3 0

Instead, break down the shape into rectangles. Next, calculate the area of both rectangles and add them together. The area of the first rectangle is 72 square centimeters and the area of the second rectangle is 50 square centimeters. Together there are 72 + 50 = 122 square centimeters.

That is how u find a irregular figure..hope this help u

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Consider the system of equations y= -2 + 4, 3y+x=-3 which statement is true of the system of equations

WINSTONCH [101]

3x-4y+2 hahahaha its not me pep perillp ie eewewr its jwghvjbe rijwte ru

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2 years ago

How can I factor 5x^2 + 26x - 24 = 0 using the completing the square method.

kifflom [539]

<h2><u>QUADRATIC EQUATION</u></h2>

<h2> $\mathbb{ANSWER:}$ </h2>

$\bold{x = 0.8 \: } \: \sf \: {\color{grey}or} \: \: \: \bold{ x= \frac{4}{5} } \\$

$\bold{x = - 6}$

— — — — — — — — — —

<h3>Step-by-step explanation:</h3>

<u>How can </u><u>we</u><u> factor 5x^2 + 26x - 24 = 0 using the completing the square </u><u>method?</u>

Let's solve your equation step-by-step.

$\bold{Given \: Equation: \color{brown} 5x²+26x-24=0}$

First, add 24 to both sides.

$\bold{5x²+26x-24 - \purple{ 24} = 0 + \purple{24}}$

$\bold{ \implies \: 5x²+26x = 24 }$

Since the coefficient of 5x² is 5, divide both sides by 5.

$\bold{ \frac{5 {x}^{2} + 26x }{5} = \frac{24}{5} } \\$

$\bold{ \implies \: {x}^{2} + \frac{26}{5} x = \frac{24}{5} } \\$

The coefficient of 26/5x is 26/5. So, let b=26/5.

Then we need to add (b/2)²=169/25 to both sides to complete the square.

Add 169/25 to both sides.

$\bold{ {x}^{2} + \frac{26}{5} x + \frac{ \purple{169}}{ \purple{25}}= \frac{24}{5} + \frac{ \purple{169}}{ \purple{25}} } \\$

$\bold{ \implies \:\bold{ {x}^{2} + \frac{26}{5} x + \frac{ 169}{ {25}}= \frac{289}{25} } } \\$

Factor the left side.

$\bold{(x + \frac{13}{5} ) {}^{2} = \frac{289}{25} } \\$

Take square root.

$\bold{x + \frac{13}{5} = ± \: \sqrt{ \frac{289}{25} }} \\$

Then, add (-13)/5 to both sides.

$\bold{x + \frac{13}{5} + \frac{\purple{ - 13} }{\purple{ 5}} = \frac{{ - 13} }{{ 5}} ± \: \sqrt{ \frac{289}{25}}} \\$

$\bold{ \: x = \frac{ - 13}{5} ± \sqrt{ \frac{289}{25} } } \\$

$\implies \: \underline{ \boxed{ \bold{ \frac{4}{5} } \sf \: \: or \: \: \bold{ x = - 6}}} \\$

_______________❖_______________

3 0

2 years ago

Read 2 more answers

Tiffany was at bat

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Answer:

6:18 hope this helps good luckkk

5 0

2 years ago

Soft drinks are sold in 2-liter bottles or 354-milliliter containers. How many liters are in 354 milliliters? please explain wel

Akimi4 [234]

The answer is 0.354 liters.

6 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST, PLEASE EXPLAIN HOW YOU GOT YOUR ANSWER!!!

Snowcat [4.5K]

Answer:
y=1/6x-6

Explanation:
What we know:
- Equation for line S: y=-6x+2
- Line T is perpendicular to line S
- Line T passes through the point (-6,-7)

To find the answer, we would need to understand two things, the first being what exactly is going on with the equation: y=-6x+2.

It’s organized in slope-intercept form, which is y=mx+b. Here’s what the variables mean:

Y=the y variable
M=the slope
X=the x variable
B=the y-intercept (the point on the line that crosses the y axis)

Knowing this, we can look at the equation for line S again: y=-6x+2. -6 is the slope of line S and 2 is the y-intercept of line S.

The second thing we need to understand is that the slope of a second line that is perpendicular to the first line is equal to the NEGATIVE RECIPROCAL of the slope of the first line.

Reciprocal: the “flip” of a fraction where the denominator and the numerator switch places

So, for example, let’s say the slope of line A=6. The slope of the line perpendicular to line A would be -1/6.

Let’s try another example: the slope of line B=-4/5. The slope of the line perpendicular to line B would be 5/4 (because two negatives makes a positive)

And here, for your question, the slope of line S=-6. Therefore, the slope of line T would be 1/6.

Awesome! We found the slope, which means so far, the equation of line T looks like this:

y=1/6x+b

All we need now is the y-intercept, which is “b” in the equation y=mx+b.

To do this, we plug in the point that the question provided us, (-6,-7), and solve. We would plug in -7 as the y variable and -6 as the x variable.

y=1/6x+b
-7=1/6(-6)+b
1) multiply 1/6 and -6
-7=-1+b
2) add 1 to both sides of the equation to isolate b
-6=b

Aha! There we have it, -6 is the y-intercept of line T.

Now, we have completed our equation:

y=1/6x-6

I hope this helps! Please comment if you have any questions.

7 0

3 years ago