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timama [110]
3 years ago
5

Is -2/3 >..<..or = -0.8

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
4 0

The answer is:

-2/3 > -0.8

Explanation:

-0.666666667 is greater than -0.8

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Mary makes biws for floral arrangements she uses 1/8 yard of ribbon for each bow how many bows can she make from two spools that
olga2289 [7]
STEP 1:
Calculate total amount of ribbon
= 2 spools * 24 yards each
= 48 yards total

STEP 2:
Divide total yards (48 yards) by portion size (1/8 yard)

= 48 ÷ 1/8
to divide fractions, we multiply by the reciprocal/inverse of 1/8
= 48 * 8/1
= 48 * 8
= 384 bows

ANSWER: She can make 384 bows.

Hope this helps! :)
5 0
3 years ago
Help please !!!! I need this I don’t need a detailed explanation
natta225 [31]
Answer:


The answer is C, -6/5
7 0
3 years ago
Read 2 more answers
A certain forest covers an area of
iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

if

4500 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year  4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year  5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year  6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0
3 years ago
A restaurant has $3,600 to spend on Advertising if each at Cost $600 how many ads will the restaurant be able to purchase
garri49 [273]

Answer:

6

Step-by-step explanation:

If a restaurant has 3600 to spend on ads which costs 600 each, then they can buy 6 ads.

They can buy 6 ads since 3600/600 = 6.

5 0
3 years ago
Read 2 more answers
30th term: a = 4, d = 12
mezya [45]

Answer:

120

Step-by-step explanation:

4*30=120

8 0
3 years ago
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