Answer:
20 visits
Step-by-step explanation:
The club that charges $40 more for enrollment charges $2 less per visit. The savings on visits is equal to the extra enrollment charge when the number of visits is 40/2 = 20.
For 20 visits, the cost at both clubs is the same.
__
If you let v represent the number of visits, ...
A = 60 +2v . . . . cost at club A
B = 20 +4v . . . . cost at club B
A = B ⇒ 60 +2v = 20 +4v . . . . . . costs are the same for "v" visits
40 = 2v . . . . . . . subtract 20+2v from both sides
40/2 = v = 20 . . . . . . same as "word solution" above
Answer: d
Step-by-step explanation:
The graph is increasing, so the base must be more than 1.
Also, the y-intercept is 2.
This leaves d.
Answer:
ω= 0.01 rad/s
Step-by-step explanation:
The given data is question is ,
- r = 100ft .
- t = 3 min = 180s.
Firstly let's find the linear speed. Which is
=> v = Circumference/time
=> v = 2πr/180s
=> v = 3.14 × 100ft ./ 90
=> v = 3.48 ft/s ≈ 1m/s
- Now the angular speed and linear speed are related as follows ,
=> v = r
=> = v/r
=> = 1/100
=> = 0.01 rad/s
<h3>
<u>Hence </u><u>the</u><u> </u><u>angular</u><u> speed</u><u> </u><u>is </u><u>0</u><u>.</u><u>0</u><u>1</u><u> </u><u>rad/</u><u>s.</u></h3>
Answer:
Pat t2 = 40 hrs
Step-by-step explanation:
Given:-
- Fred can paint a house in t1 = 10 hours.
- Pat can paint a house in t2 hours.
- pat and Fred can paint a house in T = 8 hours.
Find:-
Which equation, when solved will produce the number of hours need for pat to paint the house alone
Solution:-
- The number of people working on a particular activity " painting a house " is inversely proportional to time taken to complete the activity. tn = T. The relation for individual time taken ti to complete an activity.
Sum ( 1 / ti ) = 1 / T
Where, ti = The individual time for (ith) person
T = The total time taken to complete the time by i = n number of people.
- For n = 2,
1/t1 + 1/t2 = 1/T
1/10 + 1/t2 = 1/8
1 / t2 = 0.025
t2 = 40 hrs
- It takes Pat t2 = 40 hrs to complete painting the house.
