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Naddika [18.5K]
3 years ago
14

What is the answer for 5x1+2? I

Mathematics
1 answer:
tekilochka [14]3 years ago
5 0

Answer:

7

Step-by-step explanation:

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Write the equation for the line graphed below.
mrs_skeptik [129]

Answer:

y = 1/2x -1

Step-by-step explanation:

to find the y-intercept you find where the line crosses the y axis

for the slope you need to use the equation

change of y2 - change of y1

change of x2 - change of x1

3 0
3 years ago
Read 2 more answers
Can anyone help me?​
suter [353]

Answer:

0.8

Step-by-step explanation:

3(5x+2)+10=4

=15x+6+10=4

After this step you subtract 6 from each side and then subtract 10 from each side and then after that you divide 15x on each side which will give you 0.8.

8 0
3 years ago
|. Identify the following Pōints of each values.Write your ans
Dmitry_Shevchenko [17]
<h2>✒️VALUE</h2>

\\ \quad  \begin{array}{c} \qquad \bold{Distance \: \green{ Formula:}}\qquad\\ \\ \boldsymbol{ \tt d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}} \end{array}\\  \begin{array}{l} \\ 1.)\: \bold{Given:}\: \begin{cases}\tt D(- 5,6), E(2.-1),\textsf{ and }F(x,0) \\ \tt DF = EF \end{cases} \\ \\  \qquad\bold{Required:}\:\textsf{ value of }x \\ \\ \qquad \textsf{Solving for }x, \\ \\  \tt  \qquad DF = EF \\ \\  \implies\small \tt{\sqrt{(x -(- 5))^2 + (0 - 6)^2} = \sqrt{(x - 2)^2 + (0 - (-1))^2}} \\ \\   \implies\tt\sqrt{(x + 5)^2 + 36 } = \sqrt{(x - 2)^2 + 1 } \\ \\ \textsf{Squaring both sides yields} \\ \\  \implies\tt (x + 5)^2 + 36 = (x - 2)^2 + 1 \\ \\  \implies\tt x^2 + 10x + 25 + 36 = x^2 - 4x + 4 + 1 \\ \\ \implies \tt x^2 + 10x + 61 = x^2 - 4x + 5 \\ \\   \implies\tt10x + 4x = 5 - 61 \\ \\   \implies\tt14x = -56 \\ \\  \implies \red{\boxed{\tt x = -4}}\end{array}  \\  \\  \\  \\\begin{array}{l} \\ 2.)\: \bold{Given:}\: \begin{cases}\tt P(6,-1), Q(-4,-3),\textsf{ and }R(0,y) \\ \tt PR = QR \end{cases} \\ \\ \bold{Required:}\:\textsf{ value of }y \\ \\  \qquad\textsf{Solving for }y, \\ \\  \qquad\tt PR = QR \\ \\  \implies \tt\small{\sqrt{(0 - 6)^2 + (y - (-1))^2} = \sqrt{(0 - (-4))^2 + (y - (-3))^2}} \\ \\   \implies\tt\sqrt{36 + (y + 1)^2} = \sqrt{16 + (y + 3)^2 } \\ \\ \textsf{Squaring both sides yields} \\ \\  \implies \tt \: 36 + (y + 1)^2 = 16 + (y + 3)^2 \\ \\  \implies\tt 36 + y^2 + 2y + 1 = 16 + y^2 + 6y + 9 \\ \\  \implies \tt \: y^2 + 2y + 37 = y^2 + 6y + 25 \\ \\  \implies \tt \: 2y - 6y = 25 - 37 \\ \\ \implies \tt -4y = -12 \\ \\   \implies\red{\boxed{ \tt y = 3}} \end{array}  \\  \\  \\ \begin{array}{l} \\ 3.)\: \bold{Given:}\: \begin{cases}\: A(4,5), B(-3,2),\textsf{ and }C(x,0) \\ \: AC = BC \end{cases} \\ \\ \bold{Required:}\:\textsf{ value of }x \\ \\  \qquad\textsf{Solving for }x, \\ \\   \qquad\tt AC = BC \\ \\ \implies\tt\small{\sqrt{(x - 4)^2 + (0 - 5)^2} = \sqrt{(x - (-3))^2 + (0 - 2)^2}} \\ \\ \implies\tt\sqrt{(x - 4)^2 + 25} = \sqrt{(x + 3)^2 + 4} \\ \\ \textsf{Squaring both sides yields} \\ \\ \implies\tt\:(x - 4)^2 + 25 = (x + 3)^2 + 4 \\ \\ \implies\tt\:x^2 - 8x + 16 + 25 = x^2 + 6x + 9 + 4 \\ \\ \implies\tt\:x^2 - 8x + 41 = x^2 + 6x + 13 \\ \\ \implies\tt-8x - 6x = 13 - 41 \\ \\\implies\tt -14x = -28 \\ \\ \implies\red{\boxed{\tt\:x = 2}} \end{array}

#CarryOnLearning

#BrainlyMathKnower

#5-MinutesAnswer

7 0
2 years ago
A farmer examines a sample of 25 cartons of eggs and finds that 3 contains cracked eggs. What is the best prediction of the numb
sertanlavr [38]
I believe it's C) 60 because ideally it would be 3 for every 25, 20 x 25 = 200, so then you would do 3 x 20 = 60
3 0
3 years ago
Read 2 more answers
write an equation for the perpendicular bisector of the line joining the two points. PLEASE do 4,5 and 6
myrzilka [38]

Answer:

4. The equation of the perpendicular bisector is y = \frac{3}{4} x - \frac{1}{8}

5. The equation of the perpendicular bisector is y = - 2x + 16

6. The equation of the perpendicular bisector is y = -\frac{3}{2} x + \frac{7}{2}

Step-by-step explanation:

Lets revise some important rules

  • The product of the slopes of the perpendicular lines is -1, that means if the slope of one of them is m, then the slope of the other is -\frac{1}{m} (reciprocal m and change its sign)
  • The perpendicular bisector of a line means another line perpendicular to it and intersect it in its mid-point
  • The formula of the slope of a line is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}
  • The mid point of a segment whose end points are (x_{1},y_{1}) and (x_{2},y_{2}) is (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})
  • The slope-intercept form of the linear equation is y = m x + b, where m is the slope and b is the y-intercept

4.

∵ The line passes through (7 , 2) and (4 , 6)

- Use the formula of the slope to find its slope

∵ x_{1} = 7 and x_{2} = 4

∵ y_{1} = 2 and y_{2} = 6

∴ m=\frac{6-2}{4-7}=\frac{4}{-3}

- Reciprocal it and change its sign to find the slope of the ⊥ line

∴ The slope of the perpendicular line = \frac{3}{4}

- Use the rule of the mid-point to find the mid-point of the line

∴ The mid-point = (\frac{7+4}{2},\frac{2+6}{2})

∴ The mid-point = (\frac{11}{2},\frac{8}{2})=(\frac{11}{2},4)

- Substitute the value of the slope in the form of the equation

∵ y = \frac{3}{4} x + b

- To find b substitute x and y in the equation by the coordinates

   of the mid-point

∵ 4 = \frac{3}{4} × \frac{11}{2} + b

∴ 4 = \frac{33}{8} + b

- Subtract  \frac{33}{8} from both sides

∴ -\frac{1}{8} = b

∴ y = \frac{3}{4} x - \frac{1}{8}

∴ The equation of the perpendicular bisector is y = \frac{3}{4} x - \frac{1}{8}

5.

∵ The line passes through (8 , 5) and (4 , 3)

- Use the formula of the slope to find its slope

∵ x_{1} = 8 and x_{2} = 4

∵ y_{1} = 5 and y_{2} = 3

∴ m=\frac{3-5}{4-8}=\frac{-2}{-4}=\frac{1}{2}

- Reciprocal it and change its sign to find the slope of the ⊥ line

∴ The slope of the perpendicular line = -2

- Use the rule of the mid-point to find the mid-point of the line

∴ The mid-point = (\frac{8+4}{2},\frac{5+3}{2})

∴ The mid-point = (\frac{12}{2},\frac{8}{2})

∴ The mid-point = (6 , 4)

- Substitute the value of the slope in the form of the equation

∵ y = - 2x + b

- To find b substitute x and y in the equation by the coordinates

   of the mid-point

∵ 4 = -2 × 6 + b

∴ 4 = -12 + b

- Add 12 to both sides

∴ 16 = b

∴ y = - 2x + 16

∴ The equation of the perpendicular bisector is y = - 2x + 16

6.

∵ The line passes through (6 , 1) and (0 , -3)

- Use the formula of the slope to find its slope

∵ x_{1} = 6 and x_{2} = 0

∵ y_{1} = 1 and y_{2} = -3

∴ m=\frac{-3-1}{0-6}=\frac{-4}{-6}=\frac{2}{3}

- Reciprocal it and change its sign to find the slope of the ⊥ line

∴ The slope of the perpendicular line = -\frac{3}{2}

- Use the rule of the mid-point to find the mid-point of the line

∴ The mid-point = (\frac{6+0}{2},\frac{1+-3}{2})

∴ The mid-point = (\frac{6}{2},\frac{-2}{2})

∴ The mid-point = (3 , -1)

- Substitute the value of the slope in the form of the equation

∵ y = -\frac{3}{2} x + b

- To find b substitute x and y in the equation by the coordinates

   of the mid-point

∵ -1 = -\frac{3}{2} × 3 + b

∴ -1 = -\frac{9}{2} + b

- Add  \frac{9}{2}  to both sides

∴ \frac{7}{2} = b

∴ y = -\frac{3}{2} x + \frac{7}{2}

∴ The equation of the perpendicular bisector is y = -\frac{3}{2} x + \frac{7}{2}

8 0
3 years ago
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