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Naddika [18.5K]
3 years ago
14

What is the answer for 5x1+2? I

Mathematics
1 answer:
tekilochka [14]3 years ago
5 0

Answer:

7

Step-by-step explanation:

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X-9= 1/4x + (1/4x + 12) + (1/4x - 3) what’s that answer?
konstantin123 [22]

Answer:

x = 72

Step-by-step explanation:

Make the problem simpler by eliminating the fractional coefficients:

x-9= 1/4x + (1/4x + 12) + (1/4x - 3), when multiplied by 4, becomes:

4x - 36 = x + x + 48 + x - 12

Summing up all the x terms, we get:

4x - 2x - x = 48 - 12 + 36

Then x = 72

7 0
3 years ago
2x+3>x+5. Solving inequalities
pochemuha
The answer is x>2 I believe.
6 0
3 years ago
Enter the common ratio for the geometric sequence below. 4,6,9,...
UNO [17]

Answer:

1.5

Step-by-step explanation:

6/4=1.5

9/6=1.5

5 0
3 years ago
Please answer this question...
irina1246 [14]

Answer:  I believe the standard deviation will remain the same, 6, choice A.

Step-by-step explanation:  Standard deviation is calkculated based on the difference of each point from the mean.  If 10 were added to each score, the mean would also increase by 10.  That would mean that the difference between the mean and each score would be exactly the same, leading to an identical standard deviation.  Sounds crazy, but that's what numbers do for a living.

4 0
3 years ago
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PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198
Elena-2011 [213]

The weight in 1980 is \frac{4k}{5} kilograms

<em><u>Solution:</u></em>

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

<em><u>To find: weight in 1980</u></em>

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

<em><u>The percentage increase is given by formula:</u></em>

\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

<em><u>Substituting the values in formula,</u></em>

25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}

Thus the weight in kilograms in 1980 is \frac{4k}{5}

7 0
3 years ago
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