D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
19 is a prime number so 1, 19
hope this helps!
Look like whatever <span>3.5×2</span> is. (7)
The pages that have diagrams is an illustration of proportions
0.46% pages have diagrams
<h3>How to determine the percentage</h3>
The given parameters are:
Total = 650 pages
Diagrams = 3 pages
The percentage of page that has diagram is then calculated as:

So, we have:

Evaluate the product

Divide

Hence, 0.46% pages have diagrams
Read more about proportions at:
brainly.com/question/1781657
The answer is D.
explain:
A^2 + b^2 = c^2