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Ann [662]
3 years ago
10

Can someone help me pls

Mathematics
1 answer:
mr_godi [17]3 years ago
7 0

Answer:

The answer is No you cannot turn it into a circle

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Which equation is perpendicular to 3x - y = 9 and goes through the point (6,6)
Lelechka [254]

Answer:

y = - \frac{1}{3} x + 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 3x - y = 9 into this form by subtracting 3x from both sides

- y = - 3x + 9 ( divide all terms by - 1 )

y = 3x - 9 ← in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{3}, thus

y = - \frac{1}{3} x + c ← is the partial equation

To find c substitute (6, 6) into the partial equation

6 = - 2 + c ⇒ c = 6 + 2 = 8

y = - \frac{1}{3} x + 8 ← equation of perpendicular line

6 0
3 years ago
True or false: sec^-1(0.5) is undefined. explain your answer
ICE Princess25 [194]

Here we get the statement:

"sec^-1(0.5) is undefined"

And we want to see if this is true or false, so let's use the properties that we know to find that this is false.

Remember that the sec function is defined as:

sec(x) = \frac{1}{cos(x)}

Then we will have:

sec^{-1}(x) = (\frac{1}{cos(x)})^{-1} =  cos(x)

Then is really trivial to see that:

sec^{-1}(0.5) =  cos(0.5) = 0.878

Then we can conclude that the function is not undefined at 0.5, so the statement is false.

Below you can see the graph of the given function, and you will see that it is never undefined.

If you want to learn more, you can read:

brainly.com/question/16453813

6 0
3 years ago
Read 2 more answers
Solve the equation 9=h/9​
abruzzese [7]
ANSWER: h=1

EXPLANATION: I hope I help
8 0
3 years ago
What is 40 3/4 as a decimal
soldier1979 [14.2K]

Answer:

40.75

Step-by-step explanation:

3/4 = 0.75

40 + 0.75= 40.75

4 0
3 years ago
Are the ratios 6:2 and 2:6 equivalent?
Alenkasestr [34]

Answer:

no

Step-by-step explanation:

5 0
3 years ago
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