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Inga [223]
3 years ago
14

What's the prime factor of 92 ?

Mathematics
2 answers:
mariarad [96]3 years ago
8 0
Prime factors are multiplying numbers that cannot be divided into smaller numbers.
Let's break down 92.
Divide 92 by 2.
2 x 46.
We can still break this down.
Divide 46 by 2.
2 x 2 x 23.
This is your prime factorization of 92.
I hope this helps!
Jlenok [28]3 years ago
7 0
92 is not a prime number and that's why this is really easy...

The answer is 2^2 × 23
You ask how
92 could be broken down in 46 by dividing it by 2 and if we divide it from 2 again we will get 23.

If you want to check you can try like this...

2^2 × 23
2^2 is 4
and 4 × 23 = 92

Did you get it I hope it helped
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Let's put more details in the figure to better understand the problem:

Let's first recall the three main trigonometric functions:

\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}

For x, we will be using the Cosine Function:

\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}(16)Cosine(45^{\circ})\text{ =  x}(16)(\frac{1}{\sqrt[]{2}})\text{ = x}\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}\text{ 8}\sqrt[]{2}\text{ = x}

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For y, we will be using the Sine Function.

\text{  Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}\text{ (16)Sine }(45^{\circ})\text{ =  y}\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}\text{ 8}\sqrt[]{2}\text{ = y}

Therefore, y = 8√2.

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