Answer:
5 cm
Step-by-step explanation:
Let the shorter side be a, longer side be b, hypotenuse be c
By Pythagorean theorem:
a² + b² = c²
a² + (a + 7)² = (a + 8)²
a² + a² + 14a + 49 = a² + 16a + 64
a² - 2a - 15 = 0
a² + 3a - 5a - 15 = 0
a(a + 3) - 5(a + 3) = 0
(a + 3)(a - 5) = 0
a = -3 or a = 5
Because a is a side length and is a positive number
a = 5
It would be 82.54 centimeters tall by the end of August so you would round it up so it would become 83 centimeters meaning that the estimate would be greater than the actual height because you would be rounding up to the nearest whole number not down.
If you want to use integer tiles to find the product of 2(-5), think of it as you having 2 groups of 5 negative tiles, that is
-1 -1
-1 -1
-1 -1
-1 -1
-1 -1
Think of it as you having each of the -1 inside it's distinct tile. Now adding up these tiles you have -10.
Therefore 2(-5) is -10 using integer tiles.
If we are to use the number line, first draw your number line, then think of it as jumping twice while each jump is -5 big.
So the first jump from 0 will land on -5 and the second jump will land on -10 and that is the required answer using the number line.
Answer:
The value of annuity is ![P_v = \$ 7929.9](https://tex.z-dn.net/?f=P_v%20%20%3D%20%20%5C%24%207929.9)
Step-by-step explanation:
From the question we are told that
The periodic payment is ![P = \$ 250](https://tex.z-dn.net/?f=P%20%20%3D%20%20%5C%24%20250)
The interest rate is ![r = 5\% = 0.05](https://tex.z-dn.net/?f=r%20%3D%20%205%5C%25%20%20%3D%20%200.05)
Frequency at which it occurs in a year is n = 4 (quarterly )
The number of years is ![t = 10 \ years](https://tex.z-dn.net/?f=t%20%3D%20%2010%20%5C%20years)
The value of the annuity is mathematically represented as
(reference EDUCBA website)
substituting values
![P_v = 250 * [1 - (1 + \frac{0.05}{4} )^{-10 * 4} ] * [\frac{(1 + \frac{0.05}{4} )}{ \frac{0.08}{4} } ]](https://tex.z-dn.net/?f=P_v%20%20%3D%20250%20%2A%20%20%5B1%20%20-%20%281%20%2B%20%5Cfrac%7B0.05%7D%7B4%7D%20%29%5E%7B-10%20%2A%204%7D%20%5D%20%2A%20%5B%5Cfrac%7B%281%20%2B%20%5Cfrac%7B0.05%7D%7B4%7D%20%29%7D%7B%20%5Cfrac%7B0.08%7D%7B4%7D%20%7D%20%5D)
![P_v = 250 * [1 - (1.0125 )^{-40} ] * [\frac{(1.0125 )}{0.0125} ]](https://tex.z-dn.net/?f=P_v%20%20%3D%20%20250%20%2A%20%20%5B1%20%20-%20%281.0125%20%29%5E%7B-40%7D%20%5D%20%2A%20%5B%5Cfrac%7B%281.0125%20%29%7D%7B0.0125%7D%20%5D)
![P_v = 250 * [0.3916 ] * [\frac{(1.0125)}{0.0125} ]](https://tex.z-dn.net/?f=P_v%20%20%3D%20%20250%20%2A%20%20%5B0.3916%20%5D%20%2A%20%5B%5Cfrac%7B%281.0125%29%7D%7B0.0125%7D%20%5D)
![P_v = \$ 7929.9](https://tex.z-dn.net/?f=P_v%20%20%3D%20%20%5C%24%207929.9)