The two diagonals intersects at right-angle for a kite
the long diagonal also bisects the short diagonal so QP = PS = QS/2 = 6/2 = 3
QPR is a right-angle triangle with QR at 5 and QR at 3
RP = sqrt (5^2 - 3^) = 4m
The "I"'s r variables, now u do 2-5 which sequels -2. now u do 4+7 and that ='s 11. now I think u take 11 and -2 and u subtract 11-(-2). or it could be change the negative into a positive and add them together.
The volume of a cube is side length cubed (s^3)
So if you know the volume then take the cube root of 1/512... which is 1/8
So each side of the cube is 1/8.
There are 6 congruent sides on a cube (picture a “dice”). Do the area of each side would be (1/8)(1/8)= 1/64 then multiply that area by 6 and reduce ... you get 6/64 = 3/32 for the surface area
the first answer is 93000000 and the second answer is 240000
