Looking at a periodic table, the metals are on the left, the transition metals in the center, the metalloids farther right, and the nonmetals at the far right of the periodic table. This means the answer is metals.
Pseudoscience refers to belief, theories and practices that claims to be scientific but which have no basis in scientific facts.
Pseudoscience has many traits two of which are:
1. It is based on dogma and uncritical belief. Counter evidence might draw hostility from pseudo scientists.
2. There is usually suppression or distortion of data. Pseudo scientists typically perform selective data gathering, in which they only gather and consider favorable data that support their claims. <span />
I can't answer this question if the structural formula is not given. However, I found a similar problem in terms of wording. Taking this problem to be solved, let's take a look at the structural formula as shown in the second picture. First, you must know the parent chain, which is the longest chain. This is a trial-and-error process. The longest chain which has a branching group that is nearest to the head is the correct numbering. In this case, the longest chain has 8 carbon atoms. Thus, the base of the name if octane. Because a 3-carbon chain is branching from the 4th carbon, the IUPAC name of the compound shown is:
<em>4-propyloctane.</em>
The following equilibrium will shift in the direction of the product:
<h3>Further explanation</h3>
Given
Reaction
4HCl + O₂ → 2H₂O + 2Cl₂
Cl₂ was removed
Required
Equilibrium changes
Solution
Reaction = - action
adding the products ⇒ Shifts in the direction of the reactants
reducing the products ⇒Shifts in the direction of the products
Cl₂ as a product, so if Cl₂ is taken or reduced, the reaction will try to maintain system equilibrium by moving to the right (product formation) ⇒ Shift in the direction of the product:
Answer:
The answer to your question is below
Explanation:
Trial 1 Trial 2
mass of Mg 0.255 g 0.353 g
mass of MgO 0.418 g 0.576 g
Chemical reaction
2Mg(s) + O₂(g) ⇒ 2MgO(s)
Question 1.
Atomic mass of Mg = 24.31 x 2 = 48.62 g
Molecular mass of MgO = 2(24.31 + 16) = 80.62 g
Trial 1
48.62 g of Mg ----------------- 80.62 g of MgO
0.255 g ---------------- x
x = (0.255 x 80.62)/48.62
x = 0.422 g of MgO
Trial 2 48.62 g of Mg ----------------- 80.62 g of MgO
0.353 g ---------------- x
x = (0.353 x 80.62)/48.62
x = 0.585 g of MgO
Question 2
Trial 1
Percent yield = 0.418/0.422 x 100 = 99%
Trial 2
Percent yield = 0.576/0.585 x 100 = 98.5%
Question 3
Average = (99 + 98.5)/2
= 98.75%
