Write the iupac name for the compound below. be sure to use correct punctuation.
1 answer:
I can't answer this question if the structural formula is not given. However, I found a similar problem in terms of wording. Taking this problem to be solved, let's take a look at the structural formula as shown in the second picture. First, you must know the parent chain, which is the longest chain. This is a trial-and-error process. The longest chain which has a branching group that is nearest to the head is the correct numbering. In this case, the longest chain has 8 carbon atoms. Thus, the base of the name if octane. Because a 3-carbon chain is branching from the 4th carbon, the IUPAC name of the compound shown is: <em>4-propyloctane.</em>
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Answer : The temperature will be, 392.462 K
Explanation :
According to the Arrhenius equation,
or,
where,
= rate constant at
=
= rate constant at
=
= activation energy for the reaction = 66.41 kJ/mole = 66410 J/mole
R = gas constant = 8.314 J/mole.K
= initial temperature = 293 K
= final temperature = ?
Now put all the given values in this formula, we get:
Therefore, the temperature will be, 392.462 K
Answer:
See explanation.
Explanation:
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In this case, since the main molecular reaction that is taken place in the beaker is:
In such a way, we understand that one breaker contained silver nitrate and the other one barium iodide. Thus, the complete molecular equations turns out:
Now, for the complete ionic equation, we just ionize the aqueous species:
Finally, for the net ionic equation we cancel out barium and nitrate ions as the spectator one because they are both sides on the equation:
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Answer : The original volume of gas is
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 800 torr
= final pressure of gas at STP = 760 torr
= initial volume of gas = ?
= final volume of gas at STP =
= initial temperature of gas =
= final temperature of gas at STP =
Now put all the given values in the above equation, we get:
Therefore, the original volume of gas is