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Natalija [7]
3 years ago
5

Calculate the wavelength (in nanometers) of a photon emitted by a hydrogen atom when its electron drops from the n = 5 to n = 3

state
Chemistry
1 answer:
tankabanditka [31]3 years ago
5 0
<span>ΔE = -RH [(1/nf2) - (1/ni2)]ΔE = -2.18 x10-18 J [(1/32) - (1/52)]ΔE = -1.55 x10-19 JE = hc/λλ = hc/Eλ = [(6.63 x10-34 J.s.) x (3.00 x1017 nm/s)] /(1.55 x10-19 J)λ = 1280nm</span>
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Serjik [45]
The movement of gases through pinhole is called effusion and the effusion rate indirectly proportional to the molar mass of gas

The lighter mass gas effuses faster than the heavier one
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7 0
3 years ago
A sample of an unknown metal has a mass of 22.4g. A graduated cylinder contains 3.2 ml of water. After the metal sample is added
Goshia [24]

Answer:

d = 14.9 g/mL

Explanation:

Given data:

Mass of metal = 22.4 g

Volume of eater = 3.2 mL

Volume of water + metal = 4.7 mL

Density of metal = ?

Solution:

Volume of metal:

Volume of metal = volume of water+ metal - volume of water

Volume of metal = 4.7 mL - 3.2 mL

Volume of metal = 1.5 mL

Density of metal:

d = m/v

d = density

m = mass

v = volume

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5 0
3 years ago
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Sergeeva-Olga [200]
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4 0
3 years ago
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marshall27 [118]

Answer:

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7 0
3 years ago
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Use bond energies to calculate ΔHrxn Δ H r x n for the reaction. 2H2(g)+O2(g)→2H2O(g) 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( g )
Olenka [21]

Answer:

\large \boxed{\text{-486 kJ}}

Explanation:

You calculate the energy required to break all the bonds in the reactants.

Then you subtract the energy needed to break all the bonds in the products.

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Bonds:          2H-H    1O=O       4H-O

D/kJ·mol⁻¹:     436      498          464

\begin{array}{rcl}\Delta H & = & \sum{mD_{\text{reactants}}} - \sum{nD_{\text{products}}}\\& = & 2 \times 436 +1 \times 498 - 4 \times 464\\&=& 1370 - 1856\\&=&\textbf{-486 kJ}\\\end{array}\\\text{The enthalpy of reaction is $\large \boxed{\textbf{-486 kJ}}$}.

3 0
3 years ago
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