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Natalija [7]
3 years ago
5

Calculate the wavelength (in nanometers) of a photon emitted by a hydrogen atom when its electron drops from the n = 5 to n = 3

state
Chemistry
1 answer:
tankabanditka [31]3 years ago
5 0
<span>ΔE = -RH [(1/nf2) - (1/ni2)]ΔE = -2.18 x10-18 J [(1/32) - (1/52)]ΔE = -1.55 x10-19 JE = hc/λλ = hc/Eλ = [(6.63 x10-34 J.s.) x (3.00 x1017 nm/s)] /(1.55 x10-19 J)λ = 1280nm</span>
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6 0
3 years ago
Which of the following processes will determine the number of moles in a sample? Dividing the mass of the sample by Avogadro's n
Olenka [21]

The answer is: Dividing the number of molecules in the sample by Avogadro's number.

The Avogadro’s number is the number of atoms in 12 grams of the isotope carbon-12 (¹²C).

Na is Avogadro number or Avogadro constant (the number of particles, in this example carbon, that are contained in the amount of substance given by one mole).

The Avogadro number has value 6.022·10²³ 1/mol in the International System of Units; Na = 6.022·10²³ 1/mol.

For example:

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6 0
3 years ago
Activation energy is what kind of chemical reaction that absorbs energy
seraphim [82]

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3 0
3 years ago
What are the flocculation basins?
Mila [183]

Answer:

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Explanation:

8 0
2 years ago
Read 2 more answers
The equilibrium constant for the reaction 2NO2(g) N2O4(g) is Keq = . If a sample at equilibrium was found to contain 0.058 M NO2
Sladkaya [172]

Answer:

\boxed{3.6}

Explanation:

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E/mol·L⁻¹:   0.058     0.012

K_{\text{eq}} = \dfrac{\text{[N$_{2}$O$_{4}$]}}{\text{[NO$_{2}$]$^{2}$}} = \dfrac{0.012}{0.058^{2}} = \mathbf{3.6} \\\\

\text{The $K_{\text{eq}}$ value would be $\boxed{\mathbf{3.6}}$}

7 0
3 years ago
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