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3 years ago

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Calculate the wavelength (in nanometers) of a photon emitted by a hydrogen atom when its electron drops from the n = 5 to n = 3

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1 answer:

tankabanditka [31]3 years ago

5 0

<span>ΔE = -RH [(1/nf2) - (1/ni2)]ΔE = -2.18 x10-18 J [(1/32) - (1/52)]ΔE = -1.55 x10-19 JE = hc/λλ = hc/Eλ = [(6.63 x10-34 J.s.) x (3.00 x1017 nm/s)] /(1.55 x10-19 J)λ = 1280nm</span>

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3 years ago

calculate the wavelength (in NM) of a photon emitted by a hydrogen atom when it's electron drops from the n=5 to the n=3 state

crimeas [40]

<span>IF WE TAKE N=1 IT IS CALLED GROUND STATE. THEN THE OTHER FOLLOWING HIGHER STATES ARE CALLED EXCITED STATES. IF THE ELECTRON IN AN ATOM JUMPS FROM A STATE TO A LOWER STATE, IT LOSES ENERGY. FROM THE GIVEN STATEMENT, THE WAY TO FIND THE ENERGY RELEASED IS GIVEN BY THE FORMULA, E(n)=(-13.6 eV)/n^2. FIRST TO FIND E(5)=(-13.6 eV)/(5)^2, WE GET E(5)=-0.544 eV. E(3)=(-13.6 eV)/(3)^2, WE GET E(3)=-1.5111 eV. THEN WE HAVE TO FIND THE ENERGY TRANSITION LEVEL. ON SUBTRACTING WE GET 0.967eV. THIS ENERGY HAS TO BE CONVERTED IN JOULES. SO WE MAKE E=0.967*(1.60*10^(-19)) J/eV, WHICH CORRESPONDS TO 0.15472*10^(-18) J. WE NEED TO FIND TO THE WAVELENGTH. THE CORRESPONDING FORMULA E = hf = hc/Î», Î» = hc/E. BY SUBSTITUTING THE KNOWN VALUES, WE GET THE ANSWER TO BE 1285.548 NM.</span>

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3 years ago

Sound travels faster through solids than it does through either liquids or gases a student could verify this statement by

irina [24]

Group of answer choices.

A. Distance that sound travels through a solid, a liquid, and a gas.

B. Pitch of sound when it passes through a solid, a liquid, and a gas.

C. Distance sound travels through a solid, a liquid, and a gas at varying temperatures.

D. Time required for sound to travel a set distance through a solid, a liquid, and a gas.

Answer:

D. Time required for sound to travel a set distance through a solid, a liquid, and a gas.

Explanation:

Sound are mechanical waves that are highly dependent on matter for their propagation and transmission.

Sound travels faster through solids than it does through either liquids or gases. A student could verify this statement by measuring the time required for sound to travel a set distance through a solid, a liquid, and a gas.

Mathematically, the time required for sound to travel is given by this formula;

$Time = \frac {distance (x)}{speed (v)}$

Hence, the time taken for sound to travel through each medium (solid, liquid and gas) would be measured, recorded and compared to one another.

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3 years ago