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2 years ago

Write the equation of the line in slope-intercept form m = 4 over 7, y-intercept (0,1)

Mathematics

1 answer:

Nata [24]2 years ago

4 0

m = 4/7, y-intercept (0,1)

Slope-intercept form: y = mx + b where m = slope and b = y-intercept

So equation

y = 4/7 x + 1

Answer

y = 4/7 x + 1

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The Marine Discovery Aquarium sells ocean-themed cookies in their gift shop. Last month, they sold 65 shark cookies and 85 clown

Cerrena [4.2K]

Answer: 130 shark cookies.

Step-by-step explanation: If you divided 170 clown fidh cookies by 85 clown fish cookies you get 2. So same as 85 times 2. Then do the same with the shark cookies. 65 times 2, that equals 130.

5 0

2 years ago

How do I solve equation 24=2a + 6

algol [13]

Answer:

Step-by-step explanation:

24 - 6 = 18 divided by 2 is 9 so a must be 9

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3 years ago

A hiking trail is 2 3/5 miles long. Lucy walks 1/2 of the trail before stopping for a water break. How many miles does Lucy walk

Misha Larkins [42]

Answer:

look at the picture I have sent

4 0

2 years ago

Read 2 more answers

You must design a closed rectangular box of width w, length l and height h, whose volume is 504 cm3. The sides of the box cost 3

Charra [1.4K]

Answer:

Dimensions will be

Length = 7.23 cm

Width = 7.23 cm

Height = 9.64 cm

Step-by-step explanation:

A closed box has length = l cm

width of the box = w cm

height of the box = h cm

Volume of the rectangular box = lwh

504 = lwh

$h=\frac{504}{lw}$

Sides which involve length and width and height, cost = 3 cents per cm²

Top and bottom of the box costs = 4 cents per cm²

Cost of the sides $C_{s}$ = 3[2(l + w)h] = 6(l + w)h

$C_{s}$ = 3[2(l + w)h]

$C_{s}=6(l+w)(\frac{504}{lw} )$

Cost of the top and the bottom $C_{(t,p)}$ = 4(2lw) = 8lw

Total cost of the box C = $3024\frac{(l+w)}{lw}$ + 8lw

= $3024[\frac{1}{l}+\frac{1}{w}]$ + 8lw

To minimize the cost of the sides

$\frac{dC}{dl}=3024(-l^{-2}+0)+8w=0$

$\frac{3024}{l^{2}}=8w$

$\frac{378}{l^{2}}=w$ ---------(1)

$\frac{dC}{dw}=3024(-w^{-2})+8l=0$

$\frac{3024}{w^{2}}=8l$

$\frac{378}{w^{2}}=l$

$w^{2}=\frac{378}{l}$ -------(2)

Now place the value of w from equation (1) to equation (2)

$(\frac{378}{l^{2}})^{2}=\frac{378}{l}$

$\frac{(378)^{2} }{l^{4}}=\frac{378}{l}$

l³ = 378

l = ∛378 = 7.23 cm

From equation (2)

$w^{2}=\frac{378}{7.23}$

$w^{2}=52.28$

w = 7.23 cm

As lwh = 504 cm³

(7.23)²h = 504

$h=\frac{504}{(7.23)^{2}}$

h = 9.64 cm

6 0

3 years ago

Two gongs strike at intervals of 24 and 40minutes respectively. At twist time will they strike together again if they start simu

solmaris [256]

Answer:

They will sound together at 2pm

Step-by-step explanation:

Now, the first thing we need to calculate is , in how many minutes will the two gongs strike together.

To be able to do this, we need to calculate the least common multiple of the two numbers 24 and 40

The lowest common multiple between both is 120

This means that the two gongs will sound together at exactly 120 minutes

Now since 1 hour is 60 minutes, this means that 120 minutes will be = 120/60 = 2 hours

Since they both sounded together at 12 noon and the next time they will be sounding is next two hours, their sounding time will thus be 12 noon + 2 hours = 2 pm

8 0

3 years ago