Given: It is given that the length of the painting is 24 inches and the width is 11 inches.
To find: Area of the mat
Solution:
The watercolor painting is 24 inches long by 11 inches wide.
So, the area of the painting is:
The length of painting with mat is = 24 in + 3 in + 3 in = 30 in
The width of painting with mat = 11 in + 3 in + 3 in = 17 in
Now to calculate the area of mat subtracts the area of painting from the area of the mat.
Hence, the area of the mat is 246 in².
Answer:
Hello!!! erz here ^^
Step-by-step explanation:
0.5 divided by 2 in standard algorithm is...
4
Answer:
x=+-√10+3
Step-by-step explanation:
x^2=6x+1
x^2-6x=1
To create a trinomial square on the left side of the equation, find a value that is
equal to the square of half of b
a is the number next to x^2
b is the number next to x
c is the last number
b is -6
half of b is -3
square of half of b is 9
put 9 on both sides of the = sign
x^2-6x+9=1+9
x^2-6x+9=10
(x-3)^2=10
take the square root of both sides of the = sign
√(x-3)^2=√10
x-3=√10
x=+-√10+3
Answer:
The current is approximately 8.571 Amps
Step-by-step explanation:
You are supposed to use Ohm's Law for this problem.
Recall that Ohm's Law gives you the relationship between voltage applied (V), resistance (R) and current (I):
If the units of resistance are ohms, and the voltage is in volts, the current will be given in Amps (amperes). Then solving for the current (I) in the above equation:
Answer:
(5,-2)
Step-by-step explanation:
In the attached file
