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ycow [4]
3 years ago
13

A developer wants to know if the houses in two different neighborhoods were built at roughly the same time. She takes a random s

ample of six houses from each neighborhood and finds their ages from local records. The accompanying table shows the data for each sample (in years). Assume that the data come from a distribution that is Normally distributed. Complete parts a through c below.
Neighborhood 1:

53, 67, 48, 63, 68, 43

Neighborhood 2:

44, 35, 39, 43, 46, 57

(a) Test the null hypothesis at a=0.05 using the pooled t-test. Identify the null and alternative hypotheses.

Compute the t-statistic. Let the difference of the sample means be y1-y2 (round to three decimal places)

Find the P-value. (round to four decimal places as needed)

State the conclusion. Recall that a=0.05.

REJECT or FAIL to REJECT H0. There is SUFFICIENT or INSUFFICIENT evidence to reject the claim that the mean age of houses is the same in the two neighborhoods.

(b) Find a 95% confidence interval using the pooled degrees of freedom.

__, __

(c) A 95% confidence interval for the mean difference in ages of houses in the two neighborhoods was (1.11, 24.89) Is this result different than the result of the pooled t-confidence interval? Explain why or why not. Choose the correct answer below.

- Yes. Since the means are fairly close, the two methods will result in essentially the same confidence intervals and hypothesis tests.

- Yes. Since the standard deviations are fairly close, the two methods will result in essentially the same confidence intervals and hypothesis tests.

- No. Since the standard deviations are fairly close, the two methods will result in essentially the same confidence intervals and hypothesis tests.

- No. Since the means are fairly close, the two methods will result in essentially the same confidence intervals and hypothesis tests.i
Mathematics
1 answer:
masha68 [24]3 years ago
8 0

Answer:

A

Step-by-step explanation:

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-9+11x-8y

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If possible please help! With 12
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b

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Orange M&M’s: The M&M’s web site says that 20% of milk chocolate M&M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

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3 years ago
What is the reciprocal of 2/3​
galina1969 [7]

Answer:

3/2 or 1 and a half

hope it helps.

just sitting here waiting for brainliest........

7 0
3 years ago
You decide to put $2,000 in a savings account to save for a $3,000 downpayment on a new car. If the account has an interest rate
DanielleElmas [232]

It takes 10.155 years until you have $3,000 ⇒ 3rd

Step-by-step explanation:

The formula for compound interest, including principal sum is:

A=P(1+\frac{r}{n})^{nt} , where

  • A is the future value of the investment/loan, including interest
  • P is the principal investment amount  
  • r is the annual interest rate (decimal)
  • n is the number of times that interest is compounded per unit t
  • t is the time the money is invested or borrowed for

∵ You decide to put $2,000 in a savings account

∴ P = 2000

∵ You want to save for $3,000

∴ A = 3000

∵ The account has an interest rate of 4% per year and is

   compounded monthly

∴ r = 4% = 4 ÷ 100 = 0.04

∴ n = 12 ⇒ compounded monthly

- Substitute all of these values in the formula above to find t

∵ 3000=2000(1+\frac{0.04}{12})^{12t}

- Divide both sides by 2000

∴ 1.5=(1+\frac{1}{300})^{12t}

∴ 1.5=(1\frac{1}{300})^{12t}

- Change the mixed number to an improper fraction

∴ (1.5)=(\frac{301}{300})^{12t}

- Insert ㏒ for both sides

∴ log(1.5)=log(\frac{301}{300})^{12t}

- Remember log(a)^{n}=nlog(a)

∴ log(1.5)=(12t)log(\frac{301}{300})

- Divide both sides by log(\frac{301}{300})

∴ 121.84 = 12 t

- Divide both sides by 12

∴ 10.155 = t

It takes 10.155 years until you have $3,000

Learn more:

You can learn more about the compound interest in brainly.com/question/4361464

#LearnwithBrainly

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