Answer:
$22,832.47
Step-by-step explanation:
$32,600.00 × 21% = $6,846.00
$32,600.00 - $6,846.00 = $25,754.00
$25,754.00 × 7.65% = $1,917.18
$25,754.00 - $1,917.18 = $23,783.82
$23,783.82 × 4% = $951.35
$23,783.82 - $951.35 = $22,832.47
Answer:
44
Step-by-step explanation:
look at the screenshot below, it should help
Answer:
Answer:
x = 3.3
EF = 31.1
FG = 21.7
Step-by-step explanation:
Step-by-step explanation:
Y = 12x - 5x - 2
first simplify the equation by subtracting like terms (in this case):
12x - 5x = 7x
y = 7x - 2
Since you are finding the x, you must isolate the x. Do the opposite of PEMDAS.(Note: because there is a equal sign, what you do to one side, you do to the other)
y = 7x - 2
y (+2) = 7x - 2 (+2)
y + 2 = 7x
(y + 2)/7 = 7x/7
x = (y + 2)/7
x = (y + 2)/7 is your answer
hope this helps
Answer:
a) P(X∩Y) = 0.2
b)
= 0.16
c) P = 0.47
Step-by-step explanation:
Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.
So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67
Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:
P(X∩Y) = P(X) + P(Y) - P(X∪Y)
P(X∩Y) = 0.36 + 0.51 - 0.67
P(X∩Y) = 0.2
On the other hand, the probability
that he must stop at the first signal but not at the second one can be calculated as:
= P(X) - P(X∩Y)
= 0.36 - 0.2 = 0.16
At the same way, the probability
that he must stop at the second signal but not at the first one can be calculated as:
= P(Y) - P(X∩Y)
= 0.51 - 0.2 = 0.31
So, the probability that he must stop at exactly one signal is:
