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Elis [28]
2 years ago
6

Write the polynomial −11x^3 − 2 − 9x^5 − 4x^2 − 6x^4 − 14x in standard form. Then give the leading coefficient. HELP ASAP! 

Mathematics
2 answers:
andrezito [222]2 years ago
8 0
Lets get started :)

Writing a polynomial is standard form means arranging them accordingly, in descending power form:

-11x³ - 2 - 9x⁵ - 4x² - 6x⁴ - 14x

The highest power is 5, now we should arrange in decreasing manner
-9x⁵ - 6x⁴ - 11x³ - 4x² - 14x - 2

The leading coefficient is -9

nlexa [21]2 years ago
6 0
To write it in standard form, you line up the terms from the highest degree (exponent) to the lowerest
− 9x^5− 6x^4 −11x^3− 4x^2− 14x <span>− 2
the leading coefficient refers to the coefficient of the highest degree, which is -9 in this case. </span>
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Ryan earns $32,600 a year. He pays 21% of his gross income for federal, state, and local taxes. He is taxed at the FICA rate of
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Answer:

$22,832.47

Step-by-step explanation:

$32,600.00 × 21% = $6,846.00

$32,600.00 - $6,846.00 = $25,754.00

$25,754.00 × 7.65% = $1,917.18

$25,754.00 - $1,917.18 = $23,783.82

$23,783.82 × 4% = $951.35

$23,783.82 - $951.35 = $22,832.47

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3 years ago
What is 56 ÷ 7 + 3y3 when y = 4?
lesya692 [45]

Answer:

44

Step-by-step explanation:

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6 0
2 years ago
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If EF = (7x + 8), FG = (9x - 8), and EG = 128, find the values of x, EF, and FG.
katrin [286]

Answer:

Answer:

x = 3.3

EF = 31.1

FG = 21.7

Step-by-step explanation:

Step-by-step explanation:

4 0
3 years ago
What is the x-intercepts of the graph of y = 12x-5x-2
hammer [34]
Y = 12x - 5x - 2

first simplify the equation by subtracting like terms (in this case):

12x - 5x = 7x

y = 7x - 2

Since you are finding the x, you must isolate the x. Do the opposite of PEMDAS.(Note: because there is a equal sign, what you do to one side, you do to the other)

y = 7x - 2

y (+2) = 7x - 2 (+2)
y + 2 = 7x
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x = (y + 2)/7


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8 0
3 years ago
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The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that
tekilochka [14]

Answer:

a) P(X∩Y) = 0.2

b) P_1 = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability P_1 that he must stop at the first signal but not at the second one can be calculated as:

P_1 = P(X) - P(X∩Y)

P_1 = 0.36 - 0.2 = 0.16

At the same way, the probability P_2 that he must stop at the second signal but not at the first one can be calculated as:

P_2 = P(Y) - P(X∩Y)

P_2 = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

P = P_1+P_2\\P=0.16+0.31\\P=0.47

7 0
2 years ago
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