Answer: The answer is (A) [0,100].
Step-by-step explanation: Given in the question that a marine biologist Kelsey determined that the population of Blue Whales off the coast of Antarctica varies with time as shown in the given graph.
The population of Blue Whales (y) is plotted on the Y-axis and the time in months (x) is plotted on the X-axis.
We need to find the range of the population of Blue Whales off the coast of Antarctica from 0 to 10 months.
We can see from the attached graph that
when x = 0, then y = 0,
when x = 10, then y = 100.
That is, when time varies between 0 to 10 months, then the population of Blue Whales varies between 0 and 100.
Thus, the correct option is (A) [0,100].
82% of 100 = 82%
Depends on what you’re asking 82% of but usually it would be of 100.. hope this helps
Let's assume there are 52 weeks in a year,
so we have , rate= 6.4/52= 0.123%
now ,
c.i = 5000[(1+0.123/100)^3×52 -1]
= $1056.911
took me a while
The equation of the line is y=2/3x + 0
Explanation: The y intercept (where the line crosses the y axis) is 0, and the slope is 2/3 (up two and 3 to the right)
Answer:
x = 7.39
Step-by-step explanation:
log(x)²=(logx)², find the value of x
log x² = log x * log x
2log x = log x * log x
2 = log x
Take the exponent pf both sides
e² = e^logx
e² = x
x = e²
x = 7.39