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otez555 [7]
3 years ago
13

Work out the size of angle ACB

Mathematics
1 answer:
ololo11 [35]3 years ago
6 0

Step-by-step explanation:

AOB=2ACB

ACB=112/2=56

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CAN SOMEONE PLEASE HELP ME!!!!
ira [324]

Answer:

A

Step-by-step explanation:

Just by looking at the graph you can eliminate some silly answers such as D and B, everything besides the slope is obvious at least:

The y int is -2

The line is negative

The standard parent function equation is just y = x with a slope of 1.

This graph is clearly a bit steeper than the normal parent function, so it has a slope that is great than -1, not less . So the only answer left is A

If you want to be sure, you can calculate the slope using rise over run and the slope should be somewhat close to -1.5 which is equal to -3/2

Thanks me later :)

4 0
3 years ago
Pls help me! (more info in photo)
goldfiish [28.3K]

Answer:

x+ 3/2y= 15

Step-by-step explanation:

8x+12y=120

To put the equation into standard form, the leading coefficient has to be 1. So, divide the whole equation by 8.

x+ 3/2y= 15

8 0
3 years ago
Why is 3 x 1/10 less than 3 x 10
DIA [1.3K]

Answer:

Why is 3 x 1/10 less than 3 x 10

Since is 3 x 1/10 = 3/10 and

3 × 10 = 30, and

30 > 3/10

Step-by-step explanation:

4 0
3 years ago
Find the equation of the linear function x 1 2 3 4 y 1 6 11 16 in slope intercept form​
Anestetic [448]

Answer:

do u still need help on this

4 0
3 years ago
GET BRAINLIEST FOR THE CORRECT ANSWER AND EXPLANATION!
Tresset [83]

Interpreting the inequality, it is found that the correct option is given by F.

------------------

  • The first equation is of the line.
  • The equal sign is present in the inequality, which means that the line is not dashed, which removes option G.

In standard form, the equation of the line is:

x + 2y = 6

2y = 6 - x

y = -0.5x + 2

Thus it is a decreasing line, which removes options J.

  • We are interested in the region on the plane below the line, that is, less than the line, which removes option H.

------------------

  • As for the second equation, the normalized equation is:

3x^2 + 3y^2 = 12

3(x^2 + y^2) = 12

x^2 + y^2 = 4

  • Thus, a circle centered at the origin and with radius 2.
  • Now, we have to check if the line x + 2y - 6 = 0, with coefficients a = 1, b = 2, c = -6, intersects the circle, of centre x = 0, y = 0
  • First, we find the following distance:

d = \sqrt{\frac{|ax + by + c|}{a^2 + b^2}}

  • Considering the coefficients of the line and the center of the circle.

d = \sqrt{\frac{|1(0) + 2(0) - 6|}{1^2 + 2^2}} = \sqrt{\frac{6}{5}} = 1.1

  • This distance is less than the radius, thus, the line intersects the circle, which removes option K, and states that the correct option is given by F.

A similar problem is given at brainly.com/question/16505684

3 0
3 years ago
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